How do I exit a for loop after logical index is found true in an array?
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I would like to exit a loop if the result is set to true in the for loop. But it always returns false if I use 'continue'. How do I resolve this?
% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
(yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
result = true;
end
% continue;
end
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VBBV
2022년 12월 4일
use inside the if-end statement
% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
(yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
result = true
break % use inside the if - condition
end
end
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VBBV
2022년 12월 4일
편집: VBBV
2022년 12월 4일
If you use outside the if condition the result state may not be saved to true if this for loop is nested inside another loop which means it will restore the result state back to false. I presume, this for loop is present inside another loop, thats why result flag is being set to false again.
If you want to avoid reuslt to set false, you need to place the result flag outside of all nested loops.
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