# Table column of strings to a matrix.

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Daniel 2022년 11월 14일
답변: Steven Lord 2022년 11월 14일
Hello,
i am beginer and i am struggling with matlab tables. I have a table column that contains strings with vectors inside
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
I would like to have a matrix with the numbers inside, like
B=[0 0 0 0 0 0 0 0;0 0 0 0 0 0 0 0;0 0 0 0 0 0 0 0;1 1 1 1 1 1 1 1]
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
How can i do this without using loops? Thank you in advance.
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Stephen23 2022년 11월 14일
편집: Stephen23 2022년 11월 14일
"I have a table column that contains strings with vectors inside "
This looks like file importing is suboptimal. You can probably change the file importing to import numeric as numeric, which most likely would be simpler and more efficient than messing around with text like this.
Jan 2022년 11월 14일
"I have a table column that contains strings with vectors inside" - no, there is no table. This is a column vector of strings. If the strings are interpreted as Matlab, they would be vectors, but they are not "inside".

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### 채택된 답변

Stephen23 2022년 11월 14일
A = ["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
M = cell2mat(cellfun(@str2num,A,'uni',0))
M = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1

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### 추가 답변 (3개)

RAGHUNATHRAJU DASHARATHA 2022년 11월 14일
As per my understanding you want to get a matrix from the string array
I will demonstarte it using the example below
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
B =extract(A,digitsPattern)
B = 4×8 string array
"0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "0" "1" "1" "1" "1" "1" "1" "1" "1"
B=str2double(B)
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
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Stephen23 2022년 11월 14일
+1 very neat.

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Steven Lord 2022년 11월 14일
A=["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"]
A = 4×1 string array
"[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[0 0 0 0 0 0 0 0]" "[1 1 1 1 1 1 1 1]"
A2 = erase(A, ["[", "]"])
A2 = 4×1 string array
"0 0 0 0 0 0 0 0" "0 0 0 0 0 0 0 0" "0 0 0 0 0 0 0 0" "1 1 1 1 1 1 1 1"
double(split(A2, ' '))
ans = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
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Jan 2022년 11월 14일
편집: Jan 2022년 11월 14일
A = ["[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[0 0 0 0 0 0 0 0]";"[1 1 1 1 1 1 1 1]"];
AC = char(A);
AC(ismember(AC, '[] ')) = [];
AC = reshape(AC, numel(A), []);
B = AC - '0'
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1
Alternative:
AC = char(extract(A, digitsPattern));
B = squeeze(AC) - '0'
B = 4×8
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1

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