I'm trying to create variable number of nested for loop depending on the length of vector. The length of each for loop depends on the number in that particular column of the vector. So for example:
if a = [2 3 3];
for i = 1:2
for j = 1:3
for k = 1:3
do something
end
end
end
I have looked around and it seems that recursive function is the best way to go about this. I know how to use a recursive function to replace a for loop but after that I'm not sure how to procede.
Here is a sample of my recursive code to replace a single for loop.
function result = h(x1)
% abc = 0;
if x1 <= 0
result = 1;
else
result = 2*h(x1-1);
end
Any help would be appreciated. Thanks!

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Adam Danz
Adam Danz 2020년 4월 3일
What's happening in do-something? If it's short, provide the code. If it's more than a dozen lines, a short description would due.

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Sean de Wolski
Sean de Wolski 2015년 3월 23일

0 개 추천

I would just use two loops, one to loop over a and one to loop on each element of a:
a = [2 3 3];
for aloop = 1:numel(a)
for ii = 1:a(ii)
do whatever
end
end

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도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

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