how to add zeros in fronts of any number in matrix

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devendra
devendra 2015년 3월 22일
답변: Jan 2015년 3월 22일
dten = datenum([1998 1 1 ;2002 12 31]);
[M] = datevec(dten(1):dten(2));
years = M(:,1);
months = M(:,2);
days = M(:,3);
i want to add zeros in front of 1, 2, 3, 4, 5, 6, 7, 8, 9 like this 01, 02, 03, 04, 05, 06, 07, 08, 09 in months and days matrix. how will do this. please help me. thank you in advance.

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Konstantinos Sofos
Konstantinos Sofos 2015년 3월 22일
편집: Konstantinos Sofos 2015년 3월 22일
Asking for this probably you do not want anymore your years, months, days vectors to be numbers but chars. Because you know from basic maths that '01' doesn't exist as type of number.
myCellMonth = cellfun(@(x) num2str(x),num2cell(months),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellMonth);
idx = idx==1; % we want to add a leading '0' only in front of 1,2,3,...9
myCellMonth(idx) = cellfun(@(x) strcat('0', x),myCellMonth(idx),'UniformOutput', false)
In the same logic you could reform days and years
Regards
  댓글 수: 5
Konstantinos Sofos
Konstantinos Sofos 2015년 3월 22일
for the ' ' (inverted commas) use {} instead of () to read the context of a char cell array as i showed above. Hope that this helps.
devendra
devendra 2015년 3월 22일
thank you so much Konstantinos Sofos for helping me.

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Jan
Jan 2015년 3월 22일
sprintf and also num2str can use the '%02d' format:
myCellMonth = cellfun(@(x) num2str(x, '%02d'), num2cell(months),'UniformOutput', false);
This inserts a leading zero, when the number has less than 2 digits. Instead of preparing cell strings, you can use sprintf directly:
for i = 1:numel(M(:,1))
filename = sprintf('3B42_daily.%04d.%02d.%02d.7.SUB.nc', year(i), month(i), day(i));
...
end

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