how to add zeros in fronts of any number in matrix

dten = datenum([1998 1 1 ;2002 12 31]);
[M] = datevec(dten(1):dten(2));
years = M(:,1);
months = M(:,2);
days = M(:,3);
i want to add zeros in front of 1, 2, 3, 4, 5, 6, 7, 8, 9 like this 01, 02, 03, 04, 05, 06, 07, 08, 09 in months and days matrix. how will do this. please help me. thank you in advance.

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Konstantinos Sofos
Konstantinos Sofos 2015년 3월 22일
편집: Konstantinos Sofos 2015년 3월 22일
Asking for this probably you do not want anymore your years, months, days vectors to be numbers but chars. Because you know from basic maths that '01' doesn't exist as type of number.
myCellMonth = cellfun(@(x) num2str(x),num2cell(months),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellMonth);
idx = idx==1; % we want to add a leading '0' only in front of 1,2,3,...9
myCellMonth(idx) = cellfun(@(x) strcat('0', x),myCellMonth(idx),'UniformOutput', false)
In the same logic you could reform days and years
Regards

댓글 수: 5

After your comment you could use the above as
filename1 = ['3B42_daily.',myCellYears{i},'.',myCellMonth{i},'.',myCellDay{i},'.7.SUB.nc']
And as an example if i = 1
filename1 = ['3B42_daily.',myCellyears{1},'.',myCellMonth{1},'.',myCelldays{1},'.7.SUB.nc']
will give you as result
filename1 =
3B42_daily.1998.01.01.7.SUB.nc
devendra
devendra 2015년 3월 22일
편집: devendra 2015년 3월 22일
thank you so much Konstantinos Sofos this is helping alot but can we remove ' ' (inverted commas) from this because this is giving this type of output.
'01'
'01'
'01'
dten = datenum([1998 1 1 ;2002 12 31]);
[M] = datevec(dten(1):dten(2));
years = M(:,1);
months = M(:,2);
days = M(:,3);
%DAYS
myCellDay = cellfun(@(x) num2str(x),num2cell(days),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellDay);
idx = idx==1;
myCellDay(idx) = cellfun(@(x) strcat('0', x),myCellDay(idx),'UniformOutput', false);
%MONTHS
myCellMonth = cellfun(@(x) num2str(x),num2cell(months),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellMonth);
idx = idx==1; % we want to add a leading '0' only in front of 1,2,3,...9
myCellMonth(idx) = cellfun(@(x) strcat('0', x),myCellMonth(idx),'UniformOutput', false);
% YEARS
myCellYears = cellfun(@(x) num2str(x),num2cell(years),'UniformOutput', false);
idx = cellfun(@(x) numel(x),myCellYears);
idx = idx==1;
myCellYears(idx) = cellfun(@(x) strcat('0', x),myCellYears(idx),'UniformOutput', false);
for i = 1:numel(M(:,1))
filename = ['3B42_daily.',myCellYears{i},'.',myCellMonth{i},'.',myCellDay{i},'.7.SUB.nc']
end
for the ' ' (inverted commas) use {} instead of () to read the context of a char cell array as i showed above. Hope that this helps.
thank you so much Konstantinos Sofos for helping me.

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추가 답변 (1개)

Jan
Jan 2015년 3월 22일
sprintf and also num2str can use the '%02d' format:
myCellMonth = cellfun(@(x) num2str(x, '%02d'), num2cell(months),'UniformOutput', false);
This inserts a leading zero, when the number has less than 2 digits. Instead of preparing cell strings, you can use sprintf directly:
for i = 1:numel(M(:,1))
filename = sprintf('3B42_daily.%04d.%02d.%02d.7.SUB.nc', year(i), month(i), day(i));
...
end

카테고리

도움말 센터File Exchange에서 Dates and Time에 대해 자세히 알아보기

질문:

2015년 3월 22일

답변:

Jan
2015년 3월 22일

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