# generate an x-matrix at every iteration by for loop

조회 수: 2(최근 30일)
Ali Al raeesi 2022년 11월 2일
편집: Bruno Luong 2022년 11월 3일
assume that my iteration is 2000 i want to generate H-matrix at every iteration, soi have 2000 H-matrices for every solution.by using for loop then i need calculate c at every iteration(random because H is a random matrix). also using use for-loop
iterations=2000; % here i assume the iterations
for i=1: iterations
H=sqrt(0.5)*(randn+1i*randn)*(1/sqrt(2)); % my H
end
for i=1: iterations
cdf(idx) = log2(det((eye(Nr(2)))+((SNR(idx)/Nt(2))*abs(H)*(abs(H'))))); % my C
end
%% modify my code because i think it wronge to generate H-matrix at every iteration then i need calculate c at every iteration
%% my H is not a matrix can you show me how to generate the H as matrix

댓글을 달려면 로그인하십시오.

### 답변(1개)

KALYAN ACHARJYA 2022년 11월 2일
편집: KALYAN ACHARJYA 2022년 11월 2일
for idx=1: 2000
H=sqrt(0.5)*(randn+1i*randn)*(1/sqrt(2)); % my H
%cdf=...
end
#If you wish to save all generated H matrix, use cell array {} to save the H matrix. For cdf case, provide us the Nr or other typical data, so that we can try
cdf(idx) = log2(det((eye(Nr(2)))+((SNR(idx)/Nt(2))*abs(H)*(abs(H'))))); % my C
##### 댓글 수: 3표시숨기기 이전 댓글 수: 2
Ali Al raeesi 2022년 11월 3일
Nt = [4 4];
Nr = [1 4];
SNR=-10;
iterations=2000;
for i=1: iterations
H[i]=sqrt(0.5)*(randn(1,2)+1i*randn(1,2))*(1/sqrt(2)); % this way my H will be generated as matrix
cdf1(idx) = log2(det((eye(Nr(1)))+((SNR(idx)/Nt(1))*abs(H)*(abs(H'))))); % c
cdf2(idx) = log2(det((eye(Nr(2)))+((SNR(idx)/Nt(2))*abs(H)*(abs(H'))))); % c
end
B = sort(cdf2(idx)); % to sort c
X-axis (Sorted c)
Y-axis(CDF: between 1/5000 to 5000/5000) by using for-loop

댓글을 달려면 로그인하십시오.

### 범주

Find more on Shifting and Sorting Matrices in Help Center and File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!