1D simulation diffusion term, polar coordinates, moving boundary condition

조회 수: 3 (최근 30일)
I am trying to integrate the system I am showing in the page 3 of the attached pdf but I am having some problems with Cw and the radius because they should reach a minimum and a maximum respectively but in my simulation they go towards +inf and -inf, and Cw is decreasing too fast. Cw0, K, Cm are parameters, I also attach the whole paper if something is not clear enough. (I am using matlab). I am using forward euler and finite difference method. It is probably better to integrate with a variable space step but I cant figure out how to do it, so I just made a big enough domain to allow the radius to increase. I have started recently cfd so be kind ahahah.
clc; clear all; close all
%% DATA
K = 1;
Diff = 4e-9;
Cw0 = 55e-3; %mol/m3
r0 = 1e-3;
L = 12e-3;
N = 200;
tf = 100;
Cm = 30e-3; %mol/m3
Cinf = 0;
%% preprocessing
h = L/N;
grid1D = linspace(0,L,N+1);
%% SOLUTION
index = find(grid1D >= r0);
dt = 0.01;
tsteps = tf/dt;
C = [Cw0.*ones(1,index(1)-1)./K,Cm*ones(1,index(end)-index(1))]';
Cplot = zeros(size(grid1D));
%loop
for t = 1:tsteps
C0 = C;
% bc 6: eq 6 integration
if t ~= 1
indexrd = find(grid1D >= rd);
for counter_bc6 = index(1):indexrd(1) - 1
int6(counter_bc6) = (-4*pi*C(counter_bc6)*grid1D(counter_bc6)^2 -4*pi*C(counter_bc6 + 1)*grid1D(counter_bc6+1)^2)*h/2;
end
Cw = sum(int6)/(4/3*pi*r0^3) + Cw0;
else
Cw = Cw0;
end
% eq 3
C(index(1)) = Cw/K;
% eq 5
if t == 1
rd = r0 + h;
else
d = -Cm + 8*Cm -8*C(indexrd(1)- 2) + C(indexrd(1)- 3);
rd = -Diff*(d)/12/h/Cm*dt + rd;
end
if (mod(rd,h)~=0)
rd = rd + (h - mod(rd,h));
end
%eq 4
indexrd_new = find(grid1D>=rd);
%expl
for i = index(1):N-1
C(i) = C0(i) + dt*(Diff/h^2*(C0(i+1) + C0(i-1) - 2*C0(i)) + 2*Diff/i/h*(C0(i+1)-C0(i-1))/h );
end
for i = indexrd_new(1) :length(C)
C(i) = Cm;
end
for i = 1:index
C(i) = Cw;
end
if (mod(t,100)==0) % => Every 50 time steps
for i=1:N-1
Cplot(i) = 0.5*(C(i+1) + C(i));
end
plot(grid1D,Cplot);
hold on
plot(grid1D(indexrd_new(1))*ones(2,1),[0.028 0.052])
%scatter(t*dt,Cw)
hold off
ylim([2.8e-2 5.2e-2])
xlim([0 L/2])
xlabel("length [m]")
ylabel("Concentration [mol/m3]")
message = sprintf('t=%d', ceil(t*dt));
time = annotation('textbox',[0.15 0.8 0.1 0.1],'String',message,'EdgeColor','k','BackgroundColor','w');
drawnow;
end
end
  댓글 수: 1
Sudarshan
Sudarshan 2022년 11월 4일
Hi Andrea,
I tried going through the paper and the code. I needed some more information on what is the result that you want to achieve as I couldnt fully understand the paper. Also, could you point out if there is any specific place in the code where I can look into?

댓글을 달려면 로그인하십시오.

채택된 답변

Andrea Somma
Andrea Somma 2022년 11월 4일
I managed to solve it with a complete different approach and non-dimensional coordinates
  댓글 수: 3
Andrea Somma
Andrea Somma 2022년 11월 4일
I will include the whole script after I will publish it for my project, I promise.
Andrea Somma
Andrea Somma 2022년 12월 19일
https://github.com/sommaa/poly_droplet

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Numerical Integration and Differential Equations에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by