Using a nested for loop to create a matrix that square roots positive integers and adds 30 to negative integers.

조회 수: 7(최근 30일)
John 2022년 10월 30일
편집: KALYAN ACHARJYA 2022년 10월 30일
for X=[4,-5,13;19,-13,21;-33,77,144]
for X>=0
Y=sqrt(X)
for X<0
Y=X+30
end
end
end
I am trying to use a nested for loop to calculates the matrix Y by calculating the square roots of all the
elements of X which are greater than or equal to 0. And for elements of X that are negative
The script should work for a matrix of any size.

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답변(1개)

KALYAN ACHARJYA 2022년 10월 30일
편집: KALYAN ACHARJYA 2022년 10월 30일
X=[4,-5,13;19,-13,21;-33,77,144]
X = 3×3
4 -5 13 19 -13 21 -33 77 144
[r,c]=size(X);
Y=zeros(length(X));
for i=1:r
for j=1:c
if X(i,j)>=0
Y(i,j)=sqrt(X(i,j));
else
Y(i,j)=X(i,j)+30;
end
end
end
Y
Y = 3×3
2.0000 25.0000 3.6056 4.3589 17.0000 4.5826 -3.0000 8.7750 12.0000
% Suggested & Efficient way
%Efficint Way
%Z=double(X<0).*30+X;
Try the other condition at your own, One way multiply & change X condition
#More:
%Efficint Way: You can make it more simpler or 1 line code
Z1=double(X<0).*X+30*double(X<0);
Z2=sqrt(double(X>=0).*X);
Y=Z1+Z2
Y = 3×3
2.0000 25.0000 3.6056 4.3589 17.0000 4.5826 -3.0000 8.7750 12.0000

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