Using a nested for loop to create a matrix that square roots positive integers and adds 30 to negative integers.

for X=[4,-5,13;19,-13,21;-33,77,144]

for X>=0

Y=sqrt(X)

for X<0

Y=X+30

end

end

end

I am trying to use a nested for loop to calculates the matrix Y by calculating the square roots of all the

elements of X which are greater than or equal to 0. And for elements of X that are negative

add 30 to the elements.

The script should work for a matrix of any size.

Answer 1

[KALYAN ACHARJYA]

X=[4,-5,13;19,-13,21;-33,77,144]

X = 3×3

4 -5 13 19 -13 21 -33 77 144

[r,c]=size(X);
Y=zeros(length(X));
for i=1:r
    for j=1:c
        if X(i,j)>=0
            Y(i,j)=sqrt(X(i,j));
        else
            Y(i,j)=X(i,j)+30;
        end
    end 
end
Y

Y = 3×3

2.0000 25.0000 3.6056 4.3589 17.0000 4.5826 -3.0000 8.7750 12.0000

% Suggested & Efficient way

%Efficint Way
%Z=double(X<0).*30+X;

Try the other condition at your own, One way multiply & change X condition

#More:

%Efficint Way: You can make it more simpler or 1 line code
Z1=double(X<0).*X+30*double(X<0);
Z2=sqrt(double(X>=0).*X);
Y=Z1+Z2

Y = 3×3

2.0000 25.0000 3.6056 4.3589 17.0000 4.5826 -3.0000 8.7750 12.0000