I am beginner in matlab, and i struggly to resolve some exercice. can I have some advice according to this task?
1-1/3+1/5-1/7+1/9-..-1/1003

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David Hill
David Hill 2022년 10월 29일

1 개 추천

n=1:502;
s=sum((-1).^(n+1)./(2*n-1))
s = 0.7849

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Alonso Mukendi Kalonji
Alonso Mukendi Kalonji 2022년 10월 29일
how did you get 502 for the loop
VBBV
VBBV 2022년 10월 29일
The highest term in the fraction of series is 1003. So it can obtained by this way 2*502-1
David Hill
David Hill 2022년 10월 29일
2*502 -1 = 1003 (last element). 2*n-1 is an expression for odd numbers.
Alonso Mukendi Kalonji
Alonso Mukendi Kalonji 2022년 10월 29일
This cod are not working
>> a = 1;
k = 502;
for x = 1:k
s = sum(((-1).^(x+1))./(2*(x-1)));
end
disp(s)
-9.9800e-04
No need for a loop. Just run the below code.
x=1:502;
s=sum((-1).^(x+1)./(2*x-1))
s = 0.7849
Maybe of interest:
syms n
s = simplify(symsum((-1)^n/(2*n+1),0,Inf))
s = 
Alonso Mukendi Kalonji
Alonso Mukendi Kalonji 2022년 10월 30일
I get it!
Thank you very much!

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