# Exacting a constant range/window of values from a matrix (skipping one cell each time).

조회 수: 2(최근 30일)
Matt 2022년 10월 27일
답변: RAGHUNATHRAJU DASHARATHA 2022년 10월 27일
Hi all,
I have a variable of values, X (1000 x 1) and want to create a separate variable, Y which is made up from values 1:24, skip one cell, then the next 24 values, skip one cell etc etc. until a certain value or the end of the matrix.
I feel like it should be reltively simple but just can't seem to quite get it right. Any help would be much appreciated.
Thanks in advance.

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### 채택된 답변

KALYAN ACHARJYA 2022년 10월 27일
data=rand(1000,1);
data(25:25:1000)=[];
temp=length(data)/24;
cell_data=mat2cell(data,24*ones(1,temp))
cell_data = 40×1 cell array
{24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double} {24×1 double}
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KALYAN ACHARJYA 2022년 10월 27일
Each cell element consist of 24x1 values, the good way to handle multiple array is using cell array, as shown in the code.

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### 추가 답변(1개)

RAGHUNATHRAJU DASHARATHA 2022년 10월 27일
As per my understanding you want to skip every 25th value of a matrix.
I will try to explain it using an example below .
A=1:1000;
B=A'
B = 1000×1
1 2 3 4 5 6 7 8 9 10
for i=1:38
B(i*25)=[];
end
output=B
output = 962×1
1 2 3 4 5 6 7 8 9 10

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