please guide me how to do if loop

hello i want to write in Matlab script that asks the user to enter a number between 1 to 3 If the user enters 1 it will show this graph below

inpt = "choose from 1 to 3 : ";

s = input(inpt);

k = 6 + 6;

size = 30 + 9;

t = linspace(-pi,pi,1000);

X = size * cos (k*t) .* cos(t);

Y = size * cos (k*t) .* sin(t);

plot(X,Y,'b*')

title('Matlab Flower')

If the user enters 2 it will show a table (( still i didn't complete it ))

If the user enters 3 it will show the Sinusoidal Graph

figure (1)

t=linspace(-pi/2,pi/2,1000);

X = 6*cos(2*pi*20*t) + 2*sin(2*pi*10*t);

plot(t,X, ‘r’)

title('Sinusoidal Graph')

and if the user inputs any other number ((more tnan 3 or below 1 )), they notice "You have picked invalid option" is displayed

please help me

Answer 1

[Walter Roberson]

while true
  s = input(inpt);
  check whether s is numeric scalar 1 2 or 3
  if it is a valid choice
    break;
  end
  give warning message
end 
process the choice

[Saleh]

i will make exactly like you did ?

[Saleh]

what about , if the user inputs any other number ((more tnan 3 or below 1 )), they notice "You have picked invalid option" is displayed

please help me

[Walter Roberson]

You put that code in where I wrote the outline "give warning message"

Most of what I wrote is outline. The literal parts are "while true" and "break"