Error using a variable as input for audioread()
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Hello.
I'm trying to load a .wav file, based on user input. For testing, I am using sample.wav. When I type audioread('sample.wav'), it works perfectly, but when I type:
fileName1 = inputdlg('Type the filename of the .wav file you would like to upload');
% A dialogue box pops up and I type sample.wav into it
audioread(fileName1);
This results in the following error:
Error using which
Argument must contain a string.
Error in audiovideo.internal.absolutePathForReading (line 7)
whichFileName = which(filename);
Error in audioread (line 74)
filename = audiovideo.internal.absolutePathForReading(...
What am I doing wrong?
댓글 수: 4
Tiba Abdulhameed
2016년 3월 3일
the problem is your file name is stored in cell type of data. you should change it to string before using audioread. you can try audioread(fileName1{1});
Tiba Abdulhameed
2016년 3월 3일
% %In addition, you can make the user select from existing files by ;
[file,path] = uigetfile({'*.wav';},'input file');
name=fullfile(path,file)
[Z, fs] =audioread(name)
Saad Rehman
2020년 4월 17일
Undefined variable "audiovideo" or class "audiovideo.internal.absolutePathForReading".
Error in audioread (line 74)
filename = audiovideo.internal.absolutePathForReading(...
I've an error. kindly guide me how can I solve it?
Geoff Hayes
2020년 4월 17일
Saad - what is the line of code that you have written to load your audio file? Are you using audioread?
답변 (1개)
Harsha KVK
2022년 7월 28일
0 개 추천
As input() takes only integers. Convert the file name to string.
fileName = string(input('Type the filename of the .wav file you would like to upload')); audioread(fileName);
카테고리
도움말 센터 및 File Exchange에서 Audio and Video Data에 대해 자세히 알아보기
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