Linear Fitting starting from a value

조회 수: 6 (최근 30일)
Nicola De Noni
Nicola De Noni 2022년 10월 10일
편집: Torsten 2022년 10월 10일
Hi everyone!
I need to fit these data [100 90 80 70 50 45 40 43 42 40 35] whom are distanced by 10 seconds.
The problem is that I would fit these data starting from the first value (100) in order to understand the slope of the line.
Is it possible?
Thanks!

채택된 답변

Torsten
Torsten 2022년 10월 10일
편집: Torsten 2022년 10월 10일
Sure. Use
l(x) = a*x + 100
as model function and fit the parameter a.
xdata = ...; % your xdata as column vector
ydata = ...; % your ydata as column vector
a = xdata\(ydata-100)
But starting from a certain x-value, the slope seems to change. You should separate the fit into two parts:
l1(x) = a*x + 100 0 <= x<= x1
l2(x) = b*x + [(a-b)*x1 + 100] x1 <= x <= x(end)

추가 답변 (1개)

Hiro Yoshino
Hiro Yoshino 2022년 10월 10일
편집: Hiro Yoshino 2022년 10월 10일
refline is the easiest way to achieve that.
y = [100 90 80 70 50 45 40 43 42 40 35];
x = 0:10:10*(length(y)-1);
plot(x,y,'o');
refline
if you want to know the coefficients:
p = polyfit(x,y,1)
p = 1×2
-0.6391 89.6818
polyfit for reference.
  댓글 수: 1
Nicola De Noni
Nicola De Noni 2022년 10월 10일
Thanks @Hiro but i would like that the fitting line passe through the first point 100,0

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