Create a 3D Hexagonal Plot with 34 holes

Hello,

I am trying to generate a Matlab code for this diagram to print at an angle of 45.6 degrees. I have attached the formula for x,y,z. Y is same whether it is at an angle or not. Only X and Z change.

•X= xcos(theta)

•Y= y

•Z= (x2-x1)sin(theta)

•X2 is the coordinate for the next point.

Dimensions of the square is •L X W X H = 80 X 65 X 25.4 mm

Answer 1

[Rishav]

Hi Omar,

Here's a MATLAB script that demonstrates how to generate a MATLAB code that will print a square at an angle of 45.6 degrees:

% Define the dimensions of the square
L = 80; % Length in mm
W = 65; % Width in mm
H = 25.4; % Height in mm

% Define the angle in degrees
theta = 45.6;

% Define the coordinates of the square's corners
% Assuming the square is centered at the origin (0, 0)
x1 = -L/2;
x2 = L/2;
y = -W/2;

% Calculate the rotated coordinates
x1_rotated = x1 * cosd(theta);
x2_rotated = x2 * cosd(theta);
z_rotated = (x2 - x1) * sind(theta);

% Plot the rotated square
figure;
hold on;
plot([x1_rotated, x2_rotated, x2_rotated, x1_rotated, x1_rotated], ...
     [y, y, y + W, y + W, y], 'b', 'LineWidth', 2);
xlabel('X');
ylabel('Y');
title('Rotated Square');
axis equal;
grid on;
hold off;

Here, cosd(theta) returns the cosine of theta in degrees.