How to trasform from cell to matrix and transpose from horizontal to vertical at the same time?

조회 수: 3(최근 30일)
Hi all,
I have a structure with a 3x1 cell. The cell contains 1x101 matrices.
I want to access the cell and trasform it to matrix but at the same time transpose it from horizontal to vertical.
My approach:
my_matrix = cat(2, Data.my_cell{:});
results in 1x303 matrix. However I want the end product to be a 101x3 matrix. Can you help?

채택된 답변

Chunru
Chunru 2022년 9월 28일
Data.my_cell{1} = randn(1, 11);
Data.my_cell{2} = randn(1, 11);
Data.my_cell{3} = randn(1, 11);
Data.my_cell
ans = 1×3 cell array
{[0.2149 0.3143 1.5503 1.4478 0.1506 0.3134 -0.6636 -2.2168 -0.5194 -0.2335 -0.2900]} {[0.9692 -0.3670 0.5063 -1.1800 0.9370 -1.0615 0.8522 -0.3298 1.0530 -0.0936 -1.3496]} {[1.5188 0.9436 -0.2293 -1.3338 -0.0037 0.3350 -0.6829 -1.1980 1.1528 -2.0141 2.1318]}
my_matrix = cell2mat(Data.my_cell(:))'
my_matrix = 11×3
0.2149 0.9692 1.5188 0.3143 -0.3670 0.9436 1.5503 0.5063 -0.2293 1.4478 -1.1800 -1.3338 0.1506 0.9370 -0.0037 0.3134 -1.0615 0.3350 -0.6636 0.8522 -0.6829 -2.2168 -0.3298 -1.1980 -0.5194 1.0530 1.1528 -0.2335 -0.0936 -2.0141

추가 답변(1개)

J. Alex Lee
J. Alex Lee 2022년 9월 28일
Just change your cat dimension to 1, then transpose later.
Data.my_cell = {rand(1,101);rand(1,101);rand(1,101)}
Data = struct with fields:
my_cell: {3×1 cell}
m = cat(1,Data.my_cell{:})'
m = 101×3
0.0638 0.2311 0.1824 0.7186 0.2615 0.6819 0.2611 0.6674 0.2513 0.0409 0.2923 0.7679 0.9161 0.4880 0.2248 0.0994 0.1821 0.5870 0.3398 0.8991 0.0166 0.8289 0.6311 0.8961 0.4964 0.8724 0.6765 0.9931 0.7334 0.0755
check that it is the same as having transposed each array in the cell first, then cat-ing
c = cellfun(@transpose,Data.my_cell,"uni",false);
p = [c{:}];
isequal(p,m)
ans = logical
1

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