Solve 2nd order ODE using Euler Method

조회 수: 69 (최근 30일)
Matt
Matt 2022년 9월 27일
댓글: Matt 2022년 10월 4일
VERY new to Matlab...
Trying to implement code to use Euler method for solving second order ODE.
Equation:
x'' + 2*z*w*x' + w*x = 2*sin(2*pi*2*t)
z and w are constants. "t" is time.
Any help would be great.
Thanks!
  댓글 수: 5
James Tursa
James Tursa 2022년 10월 4일
@Matt - FYI, when you get errors, it is best to post the entire error message along with your code. Regardless, see my answer below ...
Matt
Matt 2022년 10월 4일
Will do. Really new here so just learning the ways about this. I'll be back! :-)

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채택된 답변

James Tursa
James Tursa 2022년 10월 4일
편집: James Tursa 2022년 10월 4일
You start your loop with i=1, but that means your x_d(i-1) will be x_d(0), an invalid index, hence the error. You need to set initial values for x_d(1) and x(1), and then have your starting loop index be 2. E.g.,
x(1) = initial x value
x_d(1) = initial xdot value
for i=2:n1 % start loop index at 2
x_dd(i-1) = use (i-1) indexes on everything on rhs
x_d(i) = use (i-1) indexes on everything on rhs
x(i) = use (i-1) indexes on everything on rhs
  댓글 수: 1
Matt
Matt 2022년 10월 4일
Worked like a charm! Thank you.

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추가 답변 (1개)

Davide Masiello
Davide Masiello 2022년 9월 27일
편집: Davide Masiello 2022년 9월 27일
Hi Matt - a second order ODE can be decomposed into two first order ODEs.
The secret is to set 2 variables y as
The you have
An example code is
clear,clc
tspan = [0,1]; % integrates between times 0 and 1
x0 = [1 0]; % initial conditions for x and dx/dt
[t,X] = ode15s(@odeFun,tspan,x0); % passes functions to ODE solver
x = X(:,1);
dxdt = X(:,2);
plot(t,x)
function dydt = odeFun(t,y)
z = 1;
w = 1;
dydt(1,1) = y(2);
dydt(2,1) = 2*z*w*y(2)-w*y(1)+2*sin(2*pi*2*t);
end

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