Solve 2nd order ODE using Euler Method
조회 수: 69 (최근 30일)
이전 댓글 표시
VERY new to Matlab...
Trying to implement code to use Euler method for solving second order ODE.
Equation:
x'' + 2*z*w*x' + w*x = 2*sin(2*pi*2*t)
z and w are constants. "t" is time.
Any help would be great.
Thanks!
댓글 수: 5
James Tursa
2022년 10월 4일
@Matt - FYI, when you get errors, it is best to post the entire error message along with your code. Regardless, see my answer below ...
채택된 답변
James Tursa
2022년 10월 4일
편집: James Tursa
2022년 10월 4일
You start your loop with i=1, but that means your x_d(i-1) will be x_d(0), an invalid index, hence the error. You need to set initial values for x_d(1) and x(1), and then have your starting loop index be 2. E.g.,
x(1) = initial x value
x_d(1) = initial xdot value
for i=2:n1 % start loop index at 2
x_dd(i-1) = use (i-1) indexes on everything on rhs
x_d(i) = use (i-1) indexes on everything on rhs
x(i) = use (i-1) indexes on everything on rhs
추가 답변 (1개)
Davide Masiello
2022년 9월 27일
편집: Davide Masiello
2022년 9월 27일
Hi Matt - a second order ODE can be decomposed into two first order ODEs.
The secret is to set 2 variables y as
The you have
An example code is
clear,clc
tspan = [0,1]; % integrates between times 0 and 1
x0 = [1 0]; % initial conditions for x and dx/dt
[t,X] = ode15s(@odeFun,tspan,x0); % passes functions to ODE solver
x = X(:,1);
dxdt = X(:,2);
plot(t,x)
function dydt = odeFun(t,y)
z = 1;
w = 1;
dydt(1,1) = y(2);
dydt(2,1) = 2*z*w*y(2)-w*y(1)+2*sin(2*pi*2*t);
end
댓글 수: 1
Davide Masiello
2022년 9월 27일
For more info, I suggest reading the documentation at the following link.
참고 항목
카테고리
Help Center 및 File Exchange에서 Ordinary Differential Equations에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!