Question about converting integral formula to matlab code
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I'm trying to code an integral formula as a sum of discrete data.
That seems correct, but the result is different.
Please let me know if there are any changes to my code.
Please let me know if there is a new way.
The code I made is below.
~~~~~~~~~~~~~~~~~~~~
for r = 1:M
for p = 1:N
for f0 = 1:M0
for p0 = 1:N0-1
PSI(r,p) = PSI(r,p)+...
(1/(pi^2*Rho0^2))*...
K0(f0)*...
d_K0*d_Phi0_rad*...
U(f0,p0)*...
(Rho0*(Rho0-Rho(r)*cos(Phi_rad(p)-Phi0_rad(p0)))/(Rho0^2-2*Rho0*Rho(r)*cos(Phi_rad(p)-Phi0_rad(p0))+Rho(r)^2))*...
(norm([Rho(r)*cos(Phi_rad(p)) Rho(r)*sin(Phi_rad(p))]-[Rho0*cos(Phi0_rad(p0)) Rho0*sin(Phi0_rad(p0))])^2)*...
(exp(2*1i*K0(f0)*((norm([Rho(r)*cos(Phi_rad(p)) Rho(r)*sin(Phi_rad(p))]-[Rho0*cos(Phi0_rad(p0)) Rho0*sin(Phi0_rad(p0))]))-Rho0)));
end
end
end
end
댓글 수: 6
Torsten
2022년 9월 23일
Any reason why you don't use "integral2" ?
형준 이
2022년 9월 23일
Torsten
2022년 9월 23일
I think you should set up your problem for the use with "integral2".
형준 이
2022년 9월 23일
형준 이
2022년 9월 23일
Star Strider
2022년 9월 23일
It may be necessary to use integral iteratively with the 'ArrayValued' flag set if you are integrating an array. Check the inner integral before calculating the outer integral to be certain that it is doing what you want.
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