Elementwise shift of two matrices
조회 수: 1 (최근 30일)
이전 댓글 표시
I have two 1xn matrices each of which with different index for their minima.
For instance the minimum of matrix A is the 3rd index:
A = [9 8 7 8 9];
[i idx_A] = min(A); idx_A
whereas the minimum of matrix B is the 4th index:
B = [8 8 7 6 9];
[i idx_B] = min(B); idx_B
How can I shift these two such that they both have their minima on the same index?
One way that comes to mind is cutting matrices from left and right. At the end of the day, I wan to get a matrix that looks like below:
A = [9 8 7 8];
[i idx_A] = min(A); idx_A
B = [8 7 6 9];
[i idx_B] = min(B); idx_B
How can this be done in a way that work for all matrices with the same size?
댓글 수: 0
채택된 답변
Bruno Luong
2022년 9월 15일
편집: Bruno Luong
2022년 9월 15일
truncated matrices
[~, idx_A] = min(A);
[~, idx_B] = min(B);
di=idx_A-idx_B;
Ac=A(max(1,1+di):min(end,end+di))
Bc=B(max(1-di,1):min(end-di,end))
댓글 수: 0
추가 답변 (1개)
Walter Roberson
2022년 9월 15일
B = [8 8 7 6 9];
[i idx_B] = min(B);
circshift(B, 1-idx_B)
댓글 수: 1
Walter Roberson
2022년 9월 15일
You could examine the relative values of the indices and the length of the vectors to figure out which one would involve "less" work to move.. but it would probably involve more coding than the situation is worth.
Oh... I just had a thought: you might have a situation in which the minima for one of the vectors is beyond the length of the other vector. So if you have a hard rule about which one to shift, you could end up requiring that one of them be padded.
A = [9 8 7 8];
[~, idx_A] = min(A);
B = [8 8 7 6 9];
[~, idx_B] = min(B);
B = circshift(B, idx_A - idx_B);
A, B
참고 항목
카테고리
Help Center 및 File Exchange에서 Composite Interfaces에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!