필터 지우기
필터 지우기

sscanf in a cell array

조회 수: 9 (최근 30일)
ludvikjahn
ludvikjahn 2015년 2월 26일
댓글: Stephen23 2023년 1월 30일
good morning, I have a cell array (of strings) and I want to replace strings with corresponding numbers, but using str2double that is incredibly slow. They suggested me to use
sscanf
instead, but I'm not able to use it in a cell array. Any suggestions? Thanks
let's take for instance, [{'0.001'},{'0.34'};{'89'},{'34'};{'0.898'},{'988'}]
and use sscanf
  댓글 수: 2
ludvikjahn
ludvikjahn 2015년 2월 26일
편집: ludvikjahn 2015년 2월 26일
AH, I want the numbers to be in a matrix of the same dimensions ,no longer in a cell!
Stephen23
Stephen23 2015년 2월 26일
A neater way to define your cell array is like this:
{'0.001','0.34'; '89','34'; '0.898','988'}
and not by concatenating lots of individual cell arrays.

댓글을 달려면 로그인하십시오.

답변 (2개)

Guillaume
Guillaume 2015년 2월 26일
Testing on a 500 x 500 cell array of strings, this is the fastest method I could come up with:
m = reshape(str2num(strjoin(C)), size(C));
This takes about 2.1 seconds on my machine vs 5.4 seconds for the cyclist's answer and 4.7 seconds for Stephen's answer:
>>C = arrayfun(@(n) sprintf('%f', n), rand(500), 'UniformOutput', false);
>>tic; m1 = reshape(str2num(strjoin(C)), size(C)); toc
Elapsed time is 2.081194 seconds.
>>tic; m2 = cellfun(@str2double, C); toc
Elapsed time is 5.396223 seconds.
>>tic; m3 = cellfun(@(s)sscanf(s,'%f'), C); toc
Elapsed time is 4.759057 seconds.
However, you must have obtained that huge cell array by reading some file. Why not read that file as a matrix directly?
  댓글 수: 6
Guillaume
Guillaume 2015년 2월 27일
@ludvikjahn, in R2014b strjoin is happy with matrix, so you must have an earlier version of matlab where it can only deal with vectors. It's easily fixed though:
m = reshape(str2num(strjoin(C(:))), size(C));
On my machine it's still double the speed of Stephen's explicit loop.
As to the fact, that none of matlab built-in import function can't deal with comma as decimal point, I would submit a bug report, because it boggles the mind that that matlab can't deal with localisation properly.
Stephen23
Stephen23 2023년 1월 30일
Another approach, using a comma-separated list:
C = {'0.001','0.34'; '89','34'; '0.898','988'};
V = sscanf(sprintf(' %s',C{:}),'%f')
V = 6×1
0.0010 89.0000 0.8980 0.3400 34.0000 988.0000

댓글을 달려면 로그인하십시오.


the cyclist
the cyclist 2015년 2월 26일
Are you doing it in parallel, or via loop?
Is this slow?
s = [{'0.001'},{'0.34'};{'89'},{'34'};{'0.898'},{'988'}]
n = cellfun(@str2double,s)
  댓글 수: 1
ludvikjahn
ludvikjahn 2015년 2월 26일
편집: ludvikjahn 2015년 2월 26일
doing it in parallel, not in a loop... anyway,yes, imagine s as a 10000 x 10000 cell array

댓글을 달려면 로그인하십시오.

카테고리

Help CenterFile Exchange에서 Logical에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by