Using load for different files with varying names
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I have 25 files with .mat files, naming from data1 to data25
how to load them properly without manualy typing from 1 to 25
Here is my idea and the error
```
for i = 1:1:25
load('data%d.mat',i)
end
```
Error using load
Must be a text scalar.
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도움말 센터 및 File Exchange에서 Standard File Formats에 대해 자세히 알아보기
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