How to split a string and return only decimal numbers?

I would like to extract a vector x containing decimal numbers from this string,

myString = 'YYYY MM DD hh mm  .0200  .0325  .0375  .0425  .0475  .0525  .0575  .0625  .0675';
x = [.0200  .0325  .0375  .0425  .0475  .0525  .0575  .0625  .0675]

I have been able to split myString on the white spaces as follows,

splitstring = regexp(myString,'\s+','split');

% 'YYYY'    'MM'    'DD'    'hh'    'mm'    '.0200'    '.0325'    '.0375'

but this doesn't exclude the "words" at the start. Using '\s+[^a-zA-Z]' or '\s+[0-9]' won't return the decimal numbers either.

Answer 1

[Azzi Abdelmalek]

myString = 'YYYY MM DD hh mm  .0200  .0325  .0375  .0425  .0475  .0525  .0575  .0625  .0675';
out=regexp(myString,'\d?\.?\d+','match')

[K E]

Thanks! Never can get these right.