Indexing one particular dimension regardless of number of dimensions
조회 수: 4 (최근 30일)
이전 댓글 표시
I have a structure of several dimension (7 right now) that I will be adding dimensions to in the future. In a section of my code I need to isolate the third dimension into it's three components which right now I do like
outX = in(:,:,1,:,:,:,:); outY = in(:,:,2,:,:,:,:); outZ = in(:,:,3,:,:,:,:);
Is there a way to generalize this without having to edit the number of colons in the statement?
ex:
outX = coolFunction(in,3,1); outY = coolFunction(in,3,2); outZ = coolFunction(in,3,3);
Thanks!
댓글 수: 0
채택된 답변
Guillaume
2015년 2월 23일
function out = coolFunction(in, dim, page)
validateattributes(dim, {'numeric'}, {'scalar', 'positive', '<=', ndims(in)});
validateattributes(page, {'numeric'}, {'scalar', 'positive', '<=', size(in, dim)});
alldims = arrayfun(@(d) 1:d, size(in), 'UniformOutput', false);
alldims{dim} = page;
out = in(alldims{:});
end
댓글 수: 2
Guillaume
2015년 2월 23일
Basically, it creates a cell array (with arrayfun) where each cell is an array from 1 to the size of each dimension (what colon would do), then replace the cell of the required dimension with just the page number you want in that dimension.
추가 답변 (0개)
참고 항목
카테고리
Help Center 및 File Exchange에서 Matrices and Arrays에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!