Plotting damped sine travelling wave equation in Matlab

조회 수: 17 (최근 30일)
Jesse
Jesse 2015년 2월 20일
답변: Jesse 2020년 4월 24일
Greetings all,
Please correct me if I am wrong on any of this, but I am trying to plot a damped/attenuating sine wave of the form y(x,t)=Ae^-alpha(x) * sin(wt-Bx + phi).
Granted the sin is not in the exponential, I've been trying to code this up knowing that travelling waves have spatial as well as temporal dimensions.
The code I have after user input is:
x=0:.001:1;
Beta = 2*pi/lambda; %(lambda is user input)
y1=zeros(100,100);
for t=0:.001:1
y1(t,:)=A*sin(Beta*x-w*t + phi).exp(-alpha*x)
end
%A, alpha, w, and phi are user input as well
So I'm getting a "Subscript indices must be either real positive integers or logicals." Where am I going wrong?
Also, I am trying to plot this damped wave - do I need to use plot3? If so, why?
Thanks!
-J
  댓글 수: 1
Prasad Reddy
Prasad Reddy 2020년 4월 24일
y1(t,:)=A*sinBeta.*x-w*t+phi).*exp(-alpha.*x)
please check the above equation. it may work.
you need not to use plot3 command.

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채택된 답변

KSSV
KSSV 2020년 4월 24일
편집: KSSV 2020년 4월 24일
You index t, is taking zero for the first time. Indices cannot be negative and zero in MATLAB. You need not to use loop, you can follow as below.
clc; clear al ;
A = rand ;
lambda = rand ;
w = rand ;
phi = rand ;
alpha = rand ;
x=0:.001:1;
Beta = 2*pi/lambda; %(lambda is user input)
t=0:.001:1 ;
[X,T] = meshgrid(x,t) ;
Y1 = A*sin(Beta*X-w*T + phi).*exp(-alpha*X) ;
surf(X,T,Y1)

추가 답변 (2개)

Deepak Gupta
Deepak Gupta 2020년 4월 24일
Your y1 seems to be function of two variables x and t so yes, you will need to use plot3 at it will plot y1 against two variables.
You can try below code to find value of y1:
x=0:.001:1;
t =(0:.001:1)';
Beta = 2*pi/lambda; %(lambda is user input)
y1=zeros(1001,1001); % y1 should have same dimention as x*t matrix.
y1=A*sin(Beta*x-w*t + phi).*exp(-alpha*x)
plot3(t, x, y1)

Jesse
Jesse 2020년 4월 24일
Thanks all but this question was posted 5 years ago, and I think it had to do with some project I was working on at the time.
Thank you again for the responses and your time.

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