Issue with finding the indices of the minimum element in a 3-Dimensional Array
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For a 2D array A, the command
[row,column]=find(A==min(min(A)))
outputs the row and column indices of the minimum respectively. But using a similar technique isn't working for a 3D array. For a 10x10x11 array variance_matrix (file attached), the command
find(variance_matrix==min(min(min(variance_matrix))))
outputs the location "151" which I presume represents the element in 2nd page/sheet, 5th column and 1st row.
But, the command
[row,col,depth] = find(variance_matrix==min(min(min(variance_matrix))));
outputs an absurd answer. "depth" is shown to be a logical operator while "col" (16) exceeds the actual column size (10).
I'm hoping someone would explain what's going wrong and if there's a right way to do it for multidimensional (>=3) arrays.
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Steven Lord
2022년 9월 3일
Use the 'all' dimension argument and the 'linear' index argument to obtain the linear index of the maximum of the array considering the data in all dimensions.
A = reshape(randperm(24), [3 2 4])
[value, ind] = min(A, [], 'all', 'linear')
A(ind)
If you need the subscripts instead of the linear index, use ind2sub.
[row, column, page] = ind2sub(size(A), ind)
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