Attach new values to a matrix during loop and then get the integral with cumtrapz command

조회 수: 1 (최근 30일)
Hey there,
a matrix should be initialized and filled with values of time, a signal value and the corresponding integral.
the variable "stepcounter" functions as a control variable to identify when the step threshold is violated. Each step the corresponding integral should be calculated and in the end be added together to finally get a plot of the integral over the time values. However the time values are not steady, hence the thought of the stepcounter. A matrix is defined and should be filled with the right values for the right counter value.
Below you can find the code and I hope you can help me!
i=0;
step = 60;
stepcounter = 1;
for i=2:(length(tay))
if (Integ_MTRX(i, 1)-Integ_MTRX((i-1),1)) > step
stepcounter = stepcounter +1;
Integ_MTRX(i,3) = stepcounter;
else
Integ_MTRX(i,3) = stepcounter;
end
end
for i=1:(stepcounter)
clear temp;
temp = Integ_MTRX(Integ_MTRX(:,3)==i,:);
B(:,i) = temp(:,1);
B(:,i+1) = temp(:,2);
B(:,i+2) = cumtrapz(temp(:,1),temp(:,2));
if stepcounter < 1
B(length(B(:,1))+1:length(B(:,1))+length(temp(:,1)),i) = temp(:,1);
B(length(B(:,2))+1:length(B(:,2))+length(temp(:,2)),i) = temp(:,2);
B(length(B(:,3))+1:length(B(:,3))+length(temp(:,3)),i) = cumtrapz(temp(:,1),temp(:,2));
end
end
  댓글 수: 1
Shree Charan M L
Shree Charan M L 2023년 10월 11일
It may be useful to share additional code that would help reproducing the error.
From the above code it seems that the condition 'if stepcounter < 1' is never satisfied.

댓글을 달려면 로그인하십시오.

답변 (0개)

카테고리

Help CenterFile Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by