compare two string and pass the selected data within it

조회 수: 2 (최근 30일)
Santosh Biradar
Santosh Biradar 2022년 8월 30일
답변: Santosh Biradar 2022년 8월 30일
Hello
There are two strings.
chkDataFileName = ["20220329_112048_ADU_INPUT" ; "20220329_141153_ADU_INPUT" ; "20220329_142653_ADU_INPUT" ; "20220329_144153_ADU_INPUT" ; 20220329_160005_ADU_INPUT"]
Newlyaddednames = ["20220329_112048_1742.4" ; "20220329_112048_1760.2" ; "20220329_141153_3216.8" ; "20220329_142653_3802.2" ; "20220329_144153_4720.2" ; "20220329_160005_1738"]
for eg., compare both string, as 20220329_112048 is present in both string then it will result as,
>>BLF_Name="20220329_112048_ADU_INPUT"; SnapTime = "1742.4"
>>BLF_Name="20220329_112048_ADU_INPUT"; SnapTime = "1760.2"
Now compare both string, as 20220329_141153 is present in both string then it will send the result as,
>>BLF_Name="20220329_141153_ADU_INPUT"; SnapTime = "3216.8"
same result for rest
>>BLF_Name="20220329_142653_ADU_INPUT""; SnapTime = "3802.2"
>>BLF_Name="20220329_144153_ADU_INPUT""; SnapTime = "4720.2""
>>BLF_Name="20220329_160005_ADU_INPUT""; SnapTime = "1738"
Please let me know for brief.
Thank you
  댓글 수: 2
Image Analyst
Image Analyst 2022년 8월 30일
Will it always be the first 15 characters you're looking at when you try to match up strings? Or maybe up until you see "_ADU"?
Santosh Biradar
Santosh Biradar 2022년 8월 30일
편집: Santosh Biradar 2022년 8월 30일
Yes it will be always first 15 characters.for comparing we will consider this only 20220329_141153.
but while write final output it will be 20220329_141153_ADU_INPUT

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채택된 답변

Santosh Biradar
Santosh Biradar 2022년 8월 30일
for i=1:length(chkDataFileName)
for j=1:length(Newlyaddednames)
inpSTR=char(chkDataFileName(i));
newSTR=char(Newlyaddednames(j));
if strfind(newSTR,inpSTR(1:end-10))
BLF_Name=chkDataFileName(i)
SnapTime = newSTR(17:end)
end
end
end

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