i tried to find if there are perfect numbers in the code stating that 1 should be square of other in the same matrix or array

function b = Squared(a) n=length(a) for i=1:n for j=i:n if a(i)*a(i)==a(j) b=true break else b=false end end

Answer 1

[Swaroopa]

Hi Hannah,

You can sort the array or matrix and then use the same code.

You can also use indentation rules for better clarity.

function output = squared(arr)

n=length(arr)

output=false

for i=1:n

for j=i:n

if arr(i)*arr(i)==arr(j)

output=true

break

else

output=false

end

end

end

end

Hope it helps