Why the figure of the phase discontinuous?
이전 댓글 표시
I ploted these function by MATLAB
p=[ ( 0.9000 - 0.0010i) (0.4243 + 0.0017i) (0.1000 + 0.3000i) ]; %this function denoted by (f_k(z)).
p1=[(0.9000 + 0.0010i) (0.2121 - 0.0008i) (0.1000 - 0.3000i) (0)] ; %this function denoted by (f_b(1/z)).
As you can see from the following figures:
In the first figure I ploted the phase of the function, but it look likes discontinuous (some experts here explained that it is not discontinouos but it related to the period of the phase), but I am still confuse from this point, and to escape from this case, I ploted (in the second figure ) the cos(phase) which seems smooth. But I am still do not under stand Why the phase of these function seem as discontinus.
(If the reason related with the period of the phase) WHY the cos(phase) is smooth ,although the cos function also periodic function?
MYQUESTION IS
Why the figures of the phase in the first figure look like discontinuouse?
I would appreciate if someone could further elaborate an explanation regarding these cases.
THIS IS THE FIRST FIGURE

THIS IS THE SECOND FIGUR

채택된 답변
추가 답변 (0개)
카테고리
도움말 센터 및 File Exchange에서 Communications Toolbox에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!