how to plot hexagon inside boundary?

I have boundary coordinates and I want to fill the patch with hexagons just like honeycomb.

Pleast let me know how to do this.

Thanks

Answer 1

[dpb]

As a starting point...

N=6;
t=2*pi*(1/(2*N):1/N:1).';
x=cos(t);y=sin(t);
fill(x,y,'k')
axis square
hold on
hH=fill(x+2*max(x),y,'r');
axis square
ylim(xlim)

Those on the same row are obvious, the fillers in between need an adjustment of the x positon of only 1*x and of the height of the vertical side for y for the initial point -- then it's also tiled by 2X the X,Y position.

<fill> has a builtin replication routine that, I think, can be used to build the full array automagically, but I've not dug into just how to use it/how it works; there's not an example and didn't have time(*) to dig at the moment.

(*) Well, more like "inclination" would be more accurate... :)

[Sierra]

I want to plot hexagonal grid in geoplot. but i don't know how to do.

I attached the coordinates data and the image what i expect to plot.

Please Let me know.

Thanks.

[dpb]

I don't have the mapping toolbox to even try, sorry...all I know is what I showed before of how to generate the coordinates of a hexagon and offset set them one to another to tile them...