I have some problem with reading data in loop
cx_sum(Q) and cy_sum(Q) are not working in loop.
cx_sum and cy_sum have value 1x1622.
for Q = 1:1621
CY_sum99 = mean(cy_sum(Q),'omitnan')
CX_sum99 = mean(cx_sum(Q),'omitnan')
end
So can you solve this problem? Thank you

 채택된 답변

dpb
dpb 2022년 7월 20일

0 개 추천

But they are .. just that cy_sum(Q) is the single element of the array on each pass and the mean of a single number is the number and so the last computed value at the end of the loop is the last element of each array (if not NaN) .
You're looking for simply writing
CY_mn=mean(cy_sum,'omitnan');
CX_mn=mean(cx_sum,'omitnan');
probably...but that's guessing.

댓글 수: 3

Mingde
Mingde 2022년 7월 20일
편집: Mingde 2022년 7월 20일
thank you for you answer. if i want to change loop Q= 1:270. So are cy_sum and cx_sum working until 270? because I think if we don't need to put loop from start to end, it will show the whole data in there.
for Q = 1:270
CY_sum99 = mean(cy_sum,'omitnan')
CX_sum99 = mean(cx_sum,'omitnan')
end
I see cy_sum and cx_sum are working from 1:1622
so I want it to work in specific (start:end)
dpb
dpb 2022년 7월 20일
편집: dpb 2022년 7월 20일
No, you don't want the loop still -- you want to sub-reference the portion of the array desired.
That would be
Nlower=1; % programming practice -- don't bury "magic" numbers in code;
Nupper=270; % use variables that can change
CX_mn_UL=mean(cx_sum(Nlower:Nupper),'omintnan');
It doesn't matter over what elements you loop, the above computes the same result as the mean 270 times since you reference the full variable inside the loop.
I strongly recommend spending time reading the "Getting Started" tutorial section in the local documentation on MATLAB syntax and referencing arrays, etc., ...
Mingde
Mingde 2022년 7월 20일
Thank you so much. I appreciate it your answer.

댓글을 달려면 로그인하십시오.

추가 답변 (0개)

카테고리

도움말 센터File Exchange에서 Loops and Conditional Statements에 대해 자세히 알아보기

태그

질문:

2022년 7월 20일

편집:

dpb
2022년 7월 20일

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by