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how to solve the program?

조회 수: 1 (최근 30일)
prajith samraj
prajith samraj 2022년 7월 18일
편집: prajith samraj 2022년 7월 26일
Unrecognized function or variable 'e1'.
s1=x3.^2+x1*x3+x1.^2;
s2=x1.^4+x1.^3*x3+x1.^2*x3.^2 +x1.^2*x3.^2+x1*x3.^3 + x3.^4;
%s1=x2.^2+x1*x2+x1.^2;
%s2=x1.^4+x1.^3*x2+x1.^2*x2.^2 +x1.^2*x2.^3 + x2.^4;
%u1 = -e1-e2;
%u2 = beta*e1*k1 +gamma*e1*k2+omegaf*e1-ff2*cos(W2*t)+ff1*cos(W1*t);
u1 = -e2-e1;
u2 = beta*e1*s1 + gamma*e1*s2+omegaf*e1-ff2*cos(W2*t)+ff1*cos(W1*t);
%sys-I
dx1=x2;
dx2=-alpha*x2-omegaf*x1-beta*x1.^3- gamma*x1.^5+ff1*cos(W1*t);
%sys -II
dx3=x4+u1;
dx4=-alpha*x4-omegaf*x3-beta*x3.^3- gamma*x3.^5+ff2*cos(W2*t)+u2;
de1=dx3-dx1;
de2=dx4-dx2;
e1 = x3-x1;
e2= x4-x2;
de1=e2+u1;
de2=-alpha*e2-omegaf*e1-beta*e1*s1- gamma*e1*s2+ff2*cos(W2*t)-ff1*cos(W1*t)+u2;
dy = [dx1; dx2; dx3; dx4];
end
  댓글 수: 2
prajith samraj
prajith samraj 2022년 7월 18일
i need e1 and e2 graph. what can i do?
Lateef Adewale Kareem
Lateef Adewale Kareem 2022년 7월 19일
e1 = y(:,3)-y(:,1);
e2= y(:,4)-y(:,2);

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채택된 답변

Sam Chak
Sam Chak 2022년 7월 19일
Try manipulating the parameters to get different results.
% Solver
tspan = [0 20];
x10 = 0.11;
x20 = 0.1;
x30 = 0.21;
x40 = 0.2;
y0 = [x10; x20; x30; x40];
[t, y] = ode45(@(t, y) f(t, y), tspan, y0);
% Plots
e1 = y(:, 3) - y(:, 1);
e2 = y(:, 4) - y(:, 2);
subplot(2,1,1)
plot(t, e1), grid on, xlabel('t'), ylabel('e_{1}')
subplot(2,1,2)
plot(t, e2), grid on, xlabel('t'), ylabel('e_{2}')
function dy = f(t, y)
% parameters
alpha = 0.5;
omegaf = -1;
beta = 0.8790;
gamma = 0.3000;
W1 = 1.4450;
ff1 = 0.5381;
W2 = 1.4450;
ff2 = 0.5381;
% assignment
x1 = y(1);
x2 = y(2);
x3 = y(3);
x4 = y(4);
e1 = x3 - x1;
e2 = x4 - x2;
s1 = x3^2 + x1*x3 + x1^2;
s2 = x1^4 + (x1^3)*x3 + (x1^2)*(x3^2) + (x1^2)*(x3^2) + x1*(x3^3) + x3^4;
u1 = - e2 - e1;
u2 = beta*e1*s1 + gamma*e1*s2 + omegaf*e1 - ff2*cos(W2*t) + ff1*cos(W1*t);
% sys I
dx1 = x2;
dx2 = - alpha*x2 - omegaf*x1 - beta*x1^3 - gamma*x1^5 + ff1*cos(W1*t);
% sys II
dx3 = x4 + u1;
dx4 = - alpha*x4 - omegaf*x3 - beta*x3^3 - gamma*x3^5 + ff2*cos(W2*t) + u2;
de1 = dx3 - dx1;
de2 = dx4 - dx2;
dy = [dx1; dx2; dx3; dx4];
end
  댓글 수: 2
prajith samraj
prajith samraj 2022년 7월 19일
i need the value of e1dot and e2 dot graph
Sam Chak
Sam Chak 2022년 7월 19일
@prajith samraj, I'm a little confused now. In your comment, you clearly mentioned that you need e1 and e2 graph. Perhaps, you unintentionally confused yourself with e1dot and e2dot?
Please edit the title of your question for clarity...

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