Needing to increment a number within a sin function

I am creating a matrix which has a sin function in the diagonal. It starts with 10sin(0) and goes on to 10sin(1), 10 sin(2)... all the way to 10sin(19). How can I make this happen?

답변 (1개)

Try something like this —
S = 10*sin(diag(0:19))
S = 20×20
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 8.4147 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 9.0930 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1.4112 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 -7.5680 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 -9.5892 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 -2.7942 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 6.5699 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 9.8936 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 4.1212 0 0 0 0 0 0 0 0 0 0
See the documentation on diag for details.
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Would that be a "sin"ful answer? :)
Quite definitely!

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카테고리

도움말 센터File Exchange에서 Operating on Diagonal Matrices에 대해 자세히 알아보기

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2022년 7월 15일

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2022년 7월 15일

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