Changing elements of row after certain element

Hi,

I have a m*n matrix where some of rows are like these for exmaple

[-1,-0.65,-0.45,0,0.3,0.8,1,0.4,0.2,-0.1]

Now I need to make new row as follows

[-1,-0.65,-0.45,0,0.3,0.8,1,0,0,0]

that is once any of the elements in row becomes 1 after that all the elements will be zero.

Answer 1

[Dyuman Joshi]

For a matrix run a loop through the rows

x=[-1,-0.65,-0.45,0,0.3,0.8,1,0.4,0.2,-0.1]

x = 1×10

-1.0000 -0.6500 -0.4500 0 0.3000 0.8000 1.0000 0.4000 0.2000 -0.1000

%Code edited according to the question
x(find(x==1,1)+1:end)=0

x = 1×10

-1.0000 -0.6500 -0.4500 0 0.3000 0.8000 1.0000 0 0 0

[Rajesh]

Thanks. Working well

[Jan]

This deletes all elements after a 1. The OP asked for setting the values to 0.

find() can reply an empty matrix or a vector. This works, but only, because the colon operator ignores all elements of the vector except for the 1st one. This is at least confusing.

[Dyuman Joshi]

You are correct, Jan, my code doesn't do what OP asked. The code written is according to what I had in mind at the time.

I will edit my code accordingly.

Answer 2

[Jan]

x   = [-1,-0.65,-0.45,0,0.3,0.8,1,0.4,0.2,-0.1];
idx = find(x == 1, 1);
if ~isempty(idx)
    x(idx + 1:end) = 0;
end