Relatively easy optimization problem in Excel it's hard to implement on Matlab
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rng('default')
% creating fake data
data = randi([-1000 +1000],30,500);
yt = randi([-1000 1000],30,1);
% creating fake missing values
row = randi([1 15],1,500);
col = rand(1,500) < .5;
% imputing missing fake values
for i = 1:500
if col(i) == 1
data(1:row(i),i) = nan;
end
end
%% here starts my problem
wgts = ones(1,500); % optimal weights needs to be binary (only zero or one)
% this would be easy with matrix formulas but I have missing values at the
% beginning of the series
for j = 1:30
xt(j,:) = sum(data(j,:) .* wgts,2,'omitnan');
end
X = [xt(3:end) xt(2:end-1) xt(1:end-2)];
y = yt(3:end);
% from here I basically need to:
% maximize the Adjusted R squared of the regression fitlm(X,y)
% by changing wgts
% subject to wgts = 1 or wgts = 0
% and optionally to impose sum(wgts,'all') = some number;
% basically I need to select the data cols with the highest explanatory
% power, omitting missing data
This is easy to implement with Excel solver, but it only can handle 200 decision variables and it takes a lot of time. Thank you in advance.
댓글 수: 2
Sam Chak
2022년 7월 6일
Unsure what went wrong. Can you show your results in Excel? It is probably better to compare the performances of having the same data.
답변 (1개)
Torsten
2022년 7월 6일
편집: Torsten
2022년 7월 6일
If you accept a MATLAB solution for this problem:
min: norm(X*p-y)
s.c.
xt = data*w
0<=w<=1
w integer
where p is (3x1) and "norm" is either 1-norm or max-norm, you can use intlinprog.
If you insist at maximizing adjustable r-squared, I think you will have to use ga.
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