Partial Differentiation of a function with exponential is different from other calculators

function being tested:

first differentiation with respect to 'h' in matlab code as follows:

syms x c h s
fn1 = exp(-0.5 * (((h-c)/s)^2));
diff(fn1,h)

ans = 

I got the answer = (exp(-(c - h)^2/(2*s^2))*(2*c - 2*h))/(2*s^2)

but in other calculators I got the answer =

Is there any thing wrong with my code?

Answer 1

[Dyuman Joshi]

There's nothing wrong with your answer, it's just simplified version of it. 2 from numerator and denominator is cancelled out and 1/2 is converted to 0.5 in the exponential.