How can I find the max and min amongst a set of grouping variables?
조회 수: 7 (최근 30일)
이전 댓글 표시
I have a 150x2 matrix in which the first column contains numbers that can be considered 'grouping variables' and the second column contains values associated with those grouping variables. So a small 6x2 version would look like this
1 23
1 29
1 43
2 38
2 22
2 100
I'd like to find the maximum of the values associated with each grouping variable. Similarly the minimum amongst the values associated with each grouping variable. So the above example would yield an max of 43(for variable 1) and min of 23 (for variable 1). Similarly, max of 100 (for variable 2) and min of 22 (for variable 2). Does anybody know of a similar function or method to achieve this in Matlab?
댓글 수: 0
채택된 답변
Michael Haderlein
2015년 2월 3일
Since you didn't write if every number will occur in the first column, I allow for "missing" numbers here (it doesn't make a big difference anyway):
a=1+fix(0:.23:8)' ;
b=randi(50,length(a),1);
M=[a b]
nums=unique(M(:,1));
mmin=zeros(max(nums),1);
mmax=zeros(max(nums),1);
for cnt=1:max(nums)
mmin(nums(cnt))=min(M(M(:,1)==nums(cnt),2));
mmax(nums(cnt))=max(M(M(:,1)==nums(cnt),2));
end
If every number will occur, nums(cnt)==cnt, so the expressions inside the loop can be simplified a bit.
추가 답변 (1개)
David Young
2015년 2월 3일
% test data
data = [1 23; 1 29; 1 43; 2 38; 2 22; 2 100];
% compute minima and maxima
mins = accumarray(data(:,1), data(:,2), [], @min);
maxs = accumarray(data(:,1), data(:,2), [], @max);
Then mins(k) and maxs(k) hold the min and max for grouping variable k.
댓글 수: 3
David Young
2015년 2월 3일
The third argument specifies the size of the output array, but if you're happy to let it be determined by the values in the first argument you can just let it default by putting [].
I'm afraid I don't know which books cover relatively recent functions like accumarray.
참고 항목
카테고리
Help Center 및 File Exchange에서 Logical에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!