필터 지우기
필터 지우기

HELP! Index in position 3 exceeds array bounds. Index must not exceed 1.

조회 수: 2 (최근 30일)
Muzaffer Cagislar
Muzaffer Cagislar 2022년 6월 11일
댓글: Muzaffer Cagislar 2022년 6월 11일
% Alternating-Direction Implicit Solution Method
% u[xx]+u[yy]=u[t]
% Boundary conditions u(x,0,t) = 0 u(x,1,t) = 1
% u(0,y,t) = 0 u(1,y,t) = 1
% initial conditions u(x,y,0) = 0 0<=x<1 0<=y<1
% i = spatial index in x-direction, from 1 to R
% j = spatial index in y-direction, from 1 to S
R=21; % last x-point
S=21; % last y-point
N=20; % last time step = N+1
%% constatnts
dx = 1/(R-1);
dx2 = dx*dx;
dy = 1/(S-1);
dy2 = dy*dy;
dxdy = dx2/dy2;
dydx = dy2/dx2;
dt = dx2; % dt to dx2 for good stability and results
% independent space variables
x=0:dx:1;
y=0:dy:1;
%% sizing matrices
u=zeros(R,S,N);
u1=zeros(R,S);
t=zeros(1,N+1);
a=zeros(1,R);
b=zeros(1,R);
c=zeros(1,R);
d=zeros(1,R);
ba=zeros(1,R);
ga=zeros(1,R);
%% boundary conditions
for n=1:N
for i=1:R
u(i,S,n)=1;
end
for j=1:S
u(R,j,n)=1;
end
end
%% intermediate values
for i=1:R
u1(i,S)=1;
end
for j=1:S
u1(R,j)=1;
end
% plot initial conditions
mesh(x,y,u(:,:,1))
xlabel('x-coordinate');
ylabel('y-coordinate');
zlabel('u-Temperature');
%% time step loop
t(1)=0;
for n=1:N
t(n+1)=t(n)+2*dt;
% first pass in x-direction
% first time step - intermediate values at u1(i,j) are calculated
% constants
dx2dt=dx2/dt;
% coefficients
for j=2:S-1
b(2)=-2-dx2dt;
c(2)=1;
d(2)=-dxdy*u(2,j-1,n)+(2*dxdy-dx2dt)*u(2,j,n)-dxdy*u(2,j+1,n);
for i=3:R-2
a(i)=1;
b(i)=-2-dx2dt;
c(i)=1;
d(i)=-dxdy*u(i,j-1,n)+(2*dxdy-dx2dt)*u(i,j,n)-dxdy*u(i,j+1,n);
end
a(R-1)=1;
b(R-1)=-2-dx2dt;
d(R-1)=-1-dxdy*u(i,j-1,n)+(2*dxdy-dx2dt)*u(i,j,n)-dxdy*u(i,j+1,n);
% solution by Thomas Algorithm
ba(2)=b(2);
ga(2)=d(2)/b(2);
for i=3:R-1
ba(i)=b(i)-a(i)*c(i-1)/ba(i-1);
ga(i)=(d(i)-a(i)*ga(i-1))/ba(i);
end
% back substitution step
u1(R-1,j)=ga(R-1);
for i=R-2:-1:2
u1(i,j)=ga(i)-c(i)*u1(i+1,j,n)/ba(i);
end
end
%% second pass in y-direction
% second time step - final values at u(i,j,n+1) are calculated
% constants
dy2dt=dy2/dt;
% coefficients
for i=2:R-1
b(2)=-2-dy2dt;
c(2)=1;
d(2)=-dydx*u1(i-1,2)+(2*dydx-dy2dt)*u1(i,2)-dydx*u1(i+1,2);
for j=3:S-2
a(j)=1;
b(j)=-2-dy2dt;
c(j)=1;
d(j)=-dydx*u1(i-1,j)+(2*dydx-dy2dt)*u1(i,j)-dydx*u1(i+1,j);
end
a(S-1)=1;
b(S-1)=-2-dy2dt;
d(S-1)=-1-dydx*u1(i-1,S-1)+(2*dydx-dy2dt)*u1(i,S-1)-dydx*u1(i+1,S-1);
% solution by Thomas Algorithm
ba(2)=b(2);
ga(2)=d(2)/b(2);
for j=3:S-1
ba(j)=b(j)-a(j)*c(j-1)/ba(j-1);
ga(j)=(d(j)-a(j)*ga(j-1))/ba(j);
end
% back substitution step
u(i,S-1,n+1)=ga(S-1);
for j=S-2:-1:2
u(i,j,n+1)=ga(j)-c(j)*u(i,j+1,n+1)/ba(j);
end
end
end
Index in position 3 exceeds array bounds. Index must not exceed 1.
%% plot results
mesh(x,y,u(:,:,10))
xlabel('x-coordinate');
ylabel('y-coordinate');
zlabel('u-Temperature');
t(10)
mesh(x,y,u(:,:,20))
xlabel('x-coordinate');
ylabel('y-coordinate');
zlabel('u-Temperature');
t(20)
Index in position 3 exceeds array bounds. Index must not exceed 1.
Error in deneme1 (line 92)
u1(i,j)=ga(i)-c(i)*u1(i+1,j,n)/ba(i);
what could be the reasaon about this error? I could'n get it what it is. Can you solve and explaain please?

답변 (0개)

카테고리

Help CenterFile Exchange에서 Mathematics and Optimization에 대해 자세히 알아보기

제품


릴리스

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by