How can I dynamically create new structures out of existing ones?

조회 수: 3 (최근 30일)
GG
GG 2022년 6월 9일
편집: GG 2022년 6월 13일
Can someone help me create the updated structure?
Thank you!
  댓글 수: 3
Stephen23
Stephen23 2022년 6월 9일
편집: Stephen23 2022년 6월 9일
"I cannot name each structure by hand because there are hundreds of them. "
I didn't mention naming the structures by hand. That would be a waste of time. Why do you mention that?
"What do you mean by actual indices?"
I mean actual indices, i.e. numeric references to specific locations in an array, e.g.:
S(1).fld = ..
S(2).fld = ..
S(3).fld = ..
% ^ Actual indices, neat, simple, very efficient.
You did not use indices, you just have some fieldnames that happen to have digit characters in them. Not the same thing at all (and generally more complex to process, as I suspect to be the case here too).
But as I mentioned at the bottom of my comment, your actual task might even be solved with some simpler operation. But we cannot guess what would be required for your actual goal, because of this:
Jan
Jan 2022년 6월 9일
@Yousra Ganouma: Follow Stephen's idea: Do not hide an index in the name of a field, but create an array instead, e.g.:
Data.EES{1}
Data.EES{2}
...
Data.Space(1).ESS{1}
Then the solution to split the data would be trivial and very efficient.
With hinding an index in the name you have decided for a representation of your data, which impedes the processing massively.

댓글을 달려면 로그인하십시오.

채택된 답변

Mitch Lautigar
Mitch Lautigar 2022년 6월 9일
편집: Image Analyst 2022년 6월 9일
Convert the structure to a table, combine the tables, then convert back to structure.
Googling "struct2table" and "table2struct" will get you there.

추가 답변 (0개)

카테고리

Help CenterFile Exchange에서 Structures에 대해 자세히 알아보기

제품


릴리스

R2018b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by