Intermediate step return ```InF``` while using exp

```

aa=8e+05;

bb=1e+06;

tf=0.002;

temp=(-(bb*exp(bb*tf)-aa*exp(aa*tf))*exp(-bb*tf-aa*tf)+bb-aa)

```

Output is InF

I believe the InF comes from exp(bb*tf) and exp(aa*tf)

What should do to make this work? Thank you

Answer 1

[Walter Roberson]

aa=sym(8e+05) ;
bb =sym(1e+06) ;
tf =sym(0.002);
temp = simplify( (-(bb*exp(bb*tf)-aa*exp(aa*tf))*exp(-bb*tf-aa*tf)+bb-aa))

The answer involves two terms with exp() of -2000 and -1600, plus a constant 2000. The exp() terms are so small that they have no practical effect on the constant. The larger of the two exp() is roughly -1e-689