Forward optional args to another function
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Hi Matlab Community,
can you help me out with the following problem:
func1(obj, arg1, options)
arguments
obj
arg1 string
options.x string = ""
options.y string = ""
end
func2(arg1, options)
end
func2(obj, arg1, options)
arguments
obj
arg1 string
options.x string = ""
options.y string = ""
end
end
% func1("a", x="b", y="c")
% Throws: Invalid argument at position 2. Function requires exactly 2 positional input(s).
How to pass a struct with optional arguments to another function?
Thanks in advance
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추가 답변 (1개)
This is a terrible cludge. There must be a better way. If you don't find it, feel free to use this. It uses the fact that the x="b" syntax is an extension of the normal NameValue syntax, which you can still use with a comma separated list. Be careful with struct arrays.
This will still work if there are more options in the lower option, but if you want them to be forwarded, they must be defined in the upper function.
func1(1,"a", x="b", y="c", z2="e")
func1(1,"a", x="b", y="c", z1="d")
function func1(obj, arg1, options)
arguments
obj
arg1 string
options.x string = ""
options.y string = ""
options.z2
end
unwound_options=fieldnames(options);
unwound_options(:,2)=struct2cell(options);
unwound_options=reshape(unwound_options.',1,[]);
func2(obj, arg1,unwound_options{:})
end
function func2(obj, arg1, options)
arguments
obj
arg1 string
options.x string = ""
options.y string = ""
options.z1 string = ""
options.z2 string = ""
end
obj, arg1, options
end
댓글 수: 2
memam
2022년 6월 7일
Rik
2022년 6월 7일
I personally don't use the arguments block, so I don't know what the proper way would be. I personally just use my own functions to parse optional arguments. That also allows me to keep my code compatible with older releases and with GNU Octave.
If no other answer is posted with a better solution, please consider marking this one as accepted answer. While not perfect, it does work and accepting it may increase visibility for other people with a similar problem.
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