Problem with factorial recursive function
조회 수: 32 (최근 30일)
이전 댓글 표시
Whenever I run the code for a matrix of n values, like n=1:10, only the last 2 factorials are displayed while the rest are 0's. Would anyone be able to tell me where I have gone wrong?
Code:
function x = fact(n)
if n<=1
x = 1;
else
x = n .* fact(n-1) ;
end
end
댓글 수: 0
답변 (5개)
Titus Edelhofer
2015년 1월 28일
Hi Arun,
your code does not work for arrays because of the "if n<=1". You would need to do something like
idx = (n>1);
x(~idx) = 1;
x(idx) = n(idx).* ...
Titus
댓글 수: 3
John D'Errico
2015년 1월 28일
For how large of a value are you trying to compute the factorial? Be careful, as this could be important, since that too would blow up the recursion limits.
Regardless, as you have written it, the code will still run forever. What happens when all values of n are <= 1?
The function as you wrote it will still call fact, but with an empty array for n. so you will have fact calling fact, each time with an empty argument n.
I would add a test to stop that from happening.
Shubham Tyagi
2016년 8월 15일
I'm compiling this code with a 2*4 matrix but (dimensions doesn't match in val(i)=r(i).*fact(r(i)-1);) type error is coming.
function val=fact(r)
i=(r>1); val(~i)=1; if r==1 return end val(i)=r(i).*fact(r(i)-1); end
Image Analyst
2015년 1월 31일
Not sure what you did, but it worked fine for me. I put all this (both functions) into test.m
function test
clc;
for k = 1 : 10
kFactorial = fact(k);
fprintf('%d! = %d\n', k, kFactorial);
end
function x = fact(n)
if n<=1
x = 1;
else
x = n .* fact(n-1) ;
end
In the command window you'll see:
1! = 1
2! = 2
3! = 6
4! = 24
5! = 120
6! = 720
7! = 5040
8! = 40320
9! = 362880
10! = 3628800
댓글 수: 4
Image Analyst
2016년 8월 15일
I don't know what matrix you're talking about. Please give the code you are going to run to call your function, and show what output you'd expect to see.
If you want fact n to print out an array from the first integer to the last integer, the fact() function will need to be modified since now it's just expecting a single number, not a vector or matrix.
Torsten
2016년 8월 25일
Reshape everything to vectors and reshape back to matrices, if necessary.
Best wishes
Torsten.
Titus Edelhofer
2016년 8월 25일
Hi,
two minor changes are needed:
function x = fact(n)
x = ones(size(n));
idx = (n>1);
if any(idx)
x(idx) = n(idx).*fact(n(idx)-1);
end
First, you need to initialize x as an array of the same size as n (because for fact(n-1) otherwise the array could be smaller), giving the error you observed.
Second, protect the recursive call to fact(n-1) by doing this only if there is anything to do...
Titus
댓글 수: 1
Titus Edelhofer
2016년 8월 26일
Calling for a matrix works fine, btw.:
fact([2 3 4; 5 6 7])
ans =
2 6 24
120 720 5040
Anil Sarode
2017년 12월 26일
편집: Walter Roberson
2017년 12월 26일
sorry i copied your code :
this is the one way to solve your problem :
function file: from where you make function call each time using for loop :
n=1:10;
y=[];
for i=1:length(n)
y(i)=fact(i) ;
end
function: which do desire task
function [x] = fact(n)
if n<=1
x = 1;
else
x = n .* fact(n-1) ;
end
end
댓글 수: 0
Abdimalik
2022년 12월 14일
You don't need to read input or print anything. Your task is to complete the function factorial() which takes an integer N as input parameters and returns an integer, the factorial of N.
댓글 수: 0
참고 항목
카테고리
Help Center 및 File Exchange에서 Function Creation에 대해 자세히 알아보기
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!