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plotting piecewise functions with logarithm

cgo 님이 질문을 제출함. 27 Jan 2015
최근 활동 John D'Errico 님이 답변함. 27 Jan 2015
I am plotting a piecewise function as in below:
x_axis=[-40:0.01:40];
g=5;
if x_axis<0;
plot(x_axis, (1/40).*log(2.*(g-10)./x_axis))
else x_axis>0;
plot(x_axis, (1/40).*log(2.*(g+10)./x_axis))
xlim([2.*(g-10) 2.*(g+10)])
ylim([0 0.2])
end
The thing is, I get an error message "Warning: Imaginary parts of complex X and/or Y arguments ignored > In pcwise at 8 "
And the graph does not show the correct plots. (How could there by complex values for a log function?) Please help. Thanks

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Youssef Khmou 님의 답변 27 Jan 2015

If the input vector X is negative, log produces complex result. Try the following version :
x=[-40:0.01:40];
g=5;
if x<0;
f1=(1/40).*log(2.*(g-10)./x);
plot(x,abs(f1))
else
f2=(1/40).*log(2.*(g+10)./x);
plot(x_axis,abs(f2))
xlim([2.*(g-10) 2.*(g+10)])
ylim([0 0.2])
end

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John D'Errico 님의 답변 27 Jan 2015

How could there be complex values for a log function? Um, what is the log(-2)? Or ANY negative number for the argument?
log(-2)
ans =
0.693147180559945 + 3.14159265358979i
So what are you doing?
log(2.*(g-10)./x_axis)
g is 5, and x_axis varies from -40 to 40.
So to me, it looks like you are trying to evaluate the log of a negative number.
Part of your problem arises from the fact that an if statement does NOT apply separately to every member test you give it. For example, this does not do what you apparently think it does:
x = 1:10;
if x < 5
stuff
else
otherstuff
end
Perhaps you are confusing it with something that does do what you want:
for x = 1:10
if x < 5
stuff
else
otherstuff
end
end
In the first example I showed, x is a vector. In the second, x is a scalar, that sequentially takes on values from 1 to 10.

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