How can I replace the value of an outlier rather than delete it?

Hi! I have used this method to find and eliminate the outliers from a gaussian feature of my data set:

figure;
plot(Fetal_table.mean_value_of_short_term_variability) %Fetal_table is the table of all the features in the data set and table.mean_value_of_short_term_variability is the gaussian features in which I want to work on the outliers 
histogram(Fetal_table.mean_value_of_short_term_variability)
figure;
vec_out = isoutlier(Fetal_table.mean_value_of_short_term_variability,"grubbs");
figure 
plot(Fetal_table.mean_value_of_short_term_variability, "og"); hold on; 
Fetal_table(vec_out,:)=[]; %with that I'm deleting the outliers but I want to substitute them with a value of interest 

[Mathieu NOE]

hello

simply put the required value instead of [] (obvious answer)

it depends of course of what you mean by "value of interest" (interpolation, fixed value ,...)

is it a fixed value computed from somewhere else in your code ? if that is the case , doing the substitution is rather straigthforward

Fetal_table(vec_out,:) = new_value(s); % I want to substitute outliers with a value of interest 

Answer 1

[Nihal Reddy]

I understand you want to eliminate the outliers from a gaussian feature of the data set.

Fetal_table(vec_out,:) = [];  

In the above line of code you can just replace the “[]” with variable “value_of_interest” like this

Fetal_table(vec_out,:) = value_of_interest; 

The variable “value_of_interest” can be scalar or vector depending on your need.