Problems with declaring the variable right

Good day everyone, sadly I got the following problem with my current task that I don't know how to define the right variable for the current calculation:

for i= 0:14
    
    xkt1(i+1)= xg*sin(2*pi*F1*(k1.*T-i*T));
    
    
    
end

with:

xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
xkt1=zeros(0:14);
xkt2=zeros(0:14);

k1 is the variable and I tried syms, @(k1) and k1=[ ];, sadly nothing worked and either it had problems of converting it into double, or simply wasnt able to use it correctly, if someone with more knowledge about matlab could help me, I would be really grateful.

Sincerely

Jan C. Faber

Answer 1

[Voss]

Using symbolic k1 and xkt1:

syms k1 xkt1

xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;

for i= 0:14
    xkt1(i+1)= xg*sin(2*pi*F1*(k1.*T-i*T));
end

xkt1

xkt1 = 

% evaluate xkt1(1) at k1 = 0, get a symbolic expression:
subs(xkt1(1),k1,0)

ans = 

0

% evaluate xkt1(1) at k1 = 0, get a numeric value:
double(subs(xkt1(1),k1,0))

ans = 0

% evaluate xkt1(2) at k1 = 0, get a symbolic expression:
subs(xkt1(2),k1,0)

ans = 

% evaluate xkt1(2) at k1 = 0, get a numeric value:
double(subs(xkt1(2),k1,0))

ans = -47.4896

Alternatively, using a cell array of anonymous functions:

xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
xkt1=cell(1,15);

for i= 0:14
    xkt1{i+1}= @(k1)xg*sin(2*pi*F1*(k1.*T-i*T));
end

xkt1

xkt1 = 1×15 cell array
    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}    {@(k1)xg*sin(2*pi*F1*(k1.*T-i*T))}

% evaluate xkt1{1} at k1 = 0:
xkt1{1}(0)

ans = 0

% evaluate xkt1{2} at k1 = 0:
xkt1{2}(0)

ans = -47.4896

[Jan Faber]

Thanks a lot, I'll definitely give those options a try, when it should've worked, then I'll mark the answer as accepted.

Sincerely

Jan C. Faber

[Voss]

Sounds good. Let me know if you have any questions about it.

-_

Answer 2

[Torsten]

xg= 7*2*5*1*6*3;
xh= 3/10;
F1=3;
F2=100;
T= 1/500;
fun = @(k1,i) xg*sin(2*pi*F1*(k1-i)*T);   
fun(14,0:14)