Find zero crossings in each row of a matrix (321 x 123 double)

How can I find the no. of times the signal crosses zero. Signal is in form of a matrix (321 x 123 double), where each row represents the data one signal.

Answer 1

[Star Strider]

t = linspace(0, 5, 123);                                    % Create Data
A = sin(randi(9,5,1)*2*pi*t/5 + 2*pi*randi(9,5,1))         % Sine Curves With Varying Phases

A = 5×123

-0.0000 0.1028 0.2046 0.3041 0.4005 0.4925 0.5794 0.6602 0.7339 0.7998 0.8573 0.9057 0.9445 0.9733 0.9917 0.9997 0.9970 0.9838 0.9601 0.9263 0.8827 0.8297 0.7679 0.6979 0.6206 0.5367 0.4471 0.3528 0.2547 0.1539 -0.0000 0.3041 0.5794 0.7998 0.9445 0.9997 0.9601 0.8297 0.6206 0.3528 0.0515 -0.2547 -0.5367 -0.7679 -0.9263 -0.9970 -0.9733 -0.8573 -0.6602 -0.4005 -0.1028 0.2046 0.4925 0.7339 0.9057 0.9917 0.9838 0.8827 0.6979 0.4471 -0.0000 0.3528 0.6602 0.8827 0.9917 0.9733 0.8297 0.5794 0.2547 -0.1028 -0.4471 -0.7339 -0.9263 -0.9997 -0.9445 -0.7679 -0.4925 -0.1539 0.2046 0.5367 0.7998 0.9601 0.9970 0.9057 0.6979 0.4005 0.0515 -0.3041 -0.6206 -0.8573 -0.0000 0.3041 0.5794 0.7998 0.9445 0.9997 0.9601 0.8297 0.6206 0.3528 0.0515 -0.2547 -0.5367 -0.7679 -0.9263 -0.9970 -0.9733 -0.8573 -0.6602 -0.4005 -0.1028 0.2046 0.4925 0.7339 0.9057 0.9917 0.9838 0.8827 0.6979 0.4471 -0.0000 0.3041 0.5794 0.7998 0.9445 0.9997 0.9601 0.8297 0.6206 0.3528 0.0515 -0.2547 -0.5367 -0.7679 -0.9263 -0.9970 -0.9733 -0.8573 -0.6602 -0.4005 -0.1028 0.2046 0.4925 0.7339 0.9057 0.9917 0.9838 0.8827 0.6979 0.4471

for k = 1:size(A,1)
    zc{k} = find(diff(sign(A(k,:)),[],2));                  % Zero-Crossings For Row 'k'
end

figure
plot(t,A(1,:))
hold on
plot(t(zc{1}), zeros(size(zc{1})),'+r')
hold off
grid

figure
plot(t,A(5,:))
hold on
plot(t(zc{5}), zeros(size(zc{5})),'+r')
hold off
grid

Use interp1 in a loop for each zero crossing in each row to find the exact ‘x’ values for each zero-crossing.

.

[NotA_Programmer]

Yeah, this worked.

Thanks a lot!!

[Star Strider]

As always, my pleasure!

Answer 2

[Torsten]

https://de.mathworks.com/matlabcentral/answers/375849-finding-zero-crossings-in-a-signal

[NotA_Programmer]

Torsten, thanks for your response, but I want a seperate matrix that contains locations or indices where signal crosses 0.

The sinal is of (321 x 123 double) matrix and I want a matrix of (321 x location_where_signal_crosses_zero) but while using the below code I am getting zm of different dimension

t = [0:0.048780:6];

y = Data; %Data (321 x 123 double)

zci = @(v) find(v(:).*circshift(v(:), [-1 0]) <= 0);

zx = zci(y);