Error: Function definitions are not permitted in this context.
이전 댓글 표시
This is my function
function [ area ] = calcarea(rad )
area = pi*rad.^2
end
When I try to run it, following message shows up, "The selected section cannot be evaluated because it contains an invalid statement
Also, the command window says "Error: Function definitions are not permitted in this context"
What am I doing wrong???
채택된 답변
추가 답변 (5개)
Star Strider
2015년 1월 22일
You have to put functions such as yours in their own separate .m-files. In your situation, you would save it as: calcarea.m, and to run it from your main script, you would call it as:
area = calcarea(rad)
bahadir safak
2016년 12월 17일
편집: Walter Roberson
2018년 3월 6일
sigma=1;
thresh=1000;
disp=1;
radius=1
im=imread('11.jpg');
function [cim, r, c] = harris(im, sigma, thresh, radius, disp)
error(nargchk(2,5,nargin));
dx = [-1 0 1; -1 0 1; -1 0 1]; % Derivative masks
dy = dx';
Ix = conv2(im, dx, 'same'); % Image derivatives
Iy = conv2(im, dy, 'same');
??? Error: File: harris1.m Line: 45 Column: 1
Function definitions are not permitted in this context.
>>
???
댓글 수: 7
Image Analyst
2016년 12월 17일
You can't have a script, followed by a function in the same file. But you can have two functions, so add this to the top of the file
function harris1()
or else split those up into two different files.
bahadir safak
2016년 12월 17일
편집: Walter Roberson
2018년 3월 6일
function harris1()
sigma=1;
thresh=1000;
disp=1;
radius=1;
im=imread('11.jpg');
function [cim, r, c] = harris(im, sigma, thresh, radius, disp)
error(nargchk(2,5,nargin));
dx = [-1 0 1; -1 0 1; -1 0 1]; % Derivative masks
dy = dx';
Ix = conv2(im, dx, 'same'); % Image derivatives
Iy = conv2(im, dy, 'same');
NOT Working!!
Image Analyst
2016년 12월 17일
Of course not bahadir. You never even called harris() in your main program! Not only that, but you didn't even define what your output variables are. Try this:
function harris1()
clc;
sigma=1;
thresh=1000;
disp=1;
radius=1;
im=imread('cameraman.tif');
dblIm = double(im);
[cim, r, c] = harris(dblIm, sigma, thresh, radius, disp);
function [cim, r, c] = harris(im, sigma, thresh, radius, disp)
error(nargchk(2,5,nargin));
dx = [-1 0 1; -1 0 1; -1 0 1]; % Derivative masks
dy = dx';
Ix = conv2(im, dx, 'same'); % Image derivatives
Iy = conv2(im, dy, 'same');
% Define output variables.
cim = rand % Whatever it's supposed to be....
r = rand
c = rand
Mohammedashraf Shaikh
2017년 5월 4일
편집: Walter Roberson
2018년 3월 6일
function[d] = hcompare_EMD(h1,h2)
d = sum(abs(cumsum(h1) - cumsum(h2)));
end
img = imread('C:\Users\Hp\Desktop\col\001.jpg');
function[h] = histImage(img)
% This function calculates normalized histogram of image.
% Normalized histogram is histogram h, that has at
% each i place in it, value:
% (number of picture pixels with gray level i-1) /
% (total num of pixels in picture).
sum = 0;
[y,x] = size(img); % getting sizes of image
h = zeros(1,256); % creating output histogram array
for i = 1:1: y % runing on rows
for j = 1:1: x % running on colomns
% gray level is addtess to cell in output histogram array
% we add there 1 (bacause of current pixel (y,x) has this gray level
h(img(i,j)) = h(img(i,j)) + 1;
% pay attention to fact, that we use here pixel value as index!
end
end
h = h./(y*x);
end
% to calculate the distance between the histograms of the two images %%
%(histArray, histPattern):
function[dmap] = patDistMAp(histArray, histPattern)
[y,x,z] = size(histArray);
dmap = zeros(y,x); % output array
for i = 1:1: y % runing on rows
for j = 1:1: x % running on colomns
hist = histArray(i,j,:);
% for k = 1:1:256 % making array 1x256 from 1x1x256
% h1(k) = hist(1,1,k); % there is a permute function,
% end % but we will use it next time)
h1 = permute(squeeze(hist),[2,1]);
% Using temp variable, as MATLAB7 wants it:
temp = hcompare_EMD(histPattern,h1);
dmap(i,j) = temp;
end
end
end
Mohammedashraf Shaikh
2017년 5월 4일
편집: Mohammedashraf Shaikh
2017년 5월 4일
in above problem i am getting problem
function[d] = hcompare_EMD(h1,h2) |
Error: Function definitions are not permitted in this context.
@Mohammedashraf Shaikh: your code is badly aligned, and this makes hiding the errors easy. Once I correctly aligned your code and put each operation on its own line, then the (first) mistake is obvious, and occurs in the first five lines of code:
function[d] = hcompare_EMD(h1,h2)
d = sum(abs(cumsum(h1) - cumsum(h2)));
end
img = imread('C:\Users\Hp\Desktop\col\001.jpg');
function[h] = histImage(img)
...
You call img = ... outside of any function.
It is also possible that your first function definition occurs after some lines of code in a script. Depending on MATLAB version, this will also cause an error. See the other answers for more info on this.
Summary: Learn to align your code consistently (use the MATLAB defaults), and do not put multiple operators onto one line (especially the end for functions!). You can automatically align the code in the MATLAB Editor: select all code, then press ctrl+i.
Image Analyst
2017년 5월 4일
Rwigema james
2017년 7월 7일
편집: Image Analyst
2017년 7월 7일
function Iout = readAndPreprocessImage(filename)
I=imread(filename);
if ismatrix(I)
I = cat(3,I,I,I);
end
Iout = imresize(I,[227 227]);
end
Why am I getting this error?????
Function definitions are not permitted in this context.
댓글 수: 2
Image Analyst
2017년 7월 7일
You're putting the function definition in a place where it does not belong, such as below a script in release R2016a and earlier, or elsewhere.
Abbas Khreis
2021년 5월 16일
i have 2016a version and the error Function definitions are not permitted in this con
plz help me
Elena MEZZAPESA
2017년 11월 16일
0 개 추천
Hello, Did you solve the issues to this problem in the end? As of 2017 I still get this error ?! I am trying to understand if it is because I am using a trial version of the software. Best regards,
Elena
댓글 수: 1
Image Analyst
2017년 11월 16일
It was masked as being solved. The trial version is no different than a full version other than being time-limited to 30 days. We'd have to see your code to figure out what's going wrong with your program.
Frieder Wittmann
2018년 5월 27일
0 개 추천
This is one of the main disadvantages of MATLAB notebooks over Jupyter (python) notebooks. If I can't define functions in the middle of a script, the notebook becomes hard to read.
댓글 수: 6
Walter Roberson
2018년 5월 27일
Since R2016b, MATLAB has permitted functions to be defined inside script files.
Abbas Khreis
2021년 5월 16일
clc
clear all
function y=BUBBLE_SORT(x)
N= length(x);
if N<2
y=x;
return;
end
for i=1:N-1 ;
if(x(i)>x(i+1))
t=x(i);
x(i)=x(i+1);
x(i+1)=t;
end
end
y=BUBBLE_SORT(x(1:N-1));
y=[y x(N)];
end
this code giving me error
'''Error: File: BUBBLE_SORT.m Line: 3 Column: 11
Function definitions are not permitted in this context.'''
Walter Roberson
2021년 5월 16일
편집: Walter Roberson
2021년 5월 17일
You are using R2016a or earlier, which did not permit functions to be mixed with scripts.
If you had been using R2016b or later, you would have seen a different error, complaining about function name conflicts. In versions that permit a function to be defined in a script file, it is not permitted for one of the functions to have the ame name as the script file.
Frieder Wittmann
2021년 5월 17일
Hi thanks for your reply. Im using R2019a. Here is an example. Filename is test.m
a = 5
b = 10
function y = multiplyNumbers(a,b)
y = a * b;
end
y = multiplyNumbers(a,b)
Error: File: test.m Line: 8 Column: 1
Function definitions in a script must appear at the end of the file.
Move all statements after the "multiplyNumbers" function definition to before the first local function definition.
----
Moving the function defintion to the end of the script forces the reader to jump around. At first they might not even realize, that it's a costum function that they will find at the end of the script. In Jupyter the equivalent of the above script would have worked.
Walter Roberson
2021년 5월 17일
MATLAB is not Jupityr.
Frieder Wittmann
2021년 5월 17일
편집: Frieder Wittmann
2021년 5월 17일
It isn't, it's one of the most common competitors.
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