I try to plot t(x,y) = (x^2 - 2y^2)*e^(x-y) in Matlab and i use the following code
t=@(x,y)((x.^2-2*y.^2).*exp(x-y));
x = -1:2/50:1;
y = -2:4/50:2;
[X, Y] = meshgrid(x, y);
surf(X, Y, t(X,Y));
rotate3d on;
I got the result but it is not the same as i drawn in Geogebra
I think there is a problem with .*exp(x-y)

댓글 수: 4

Hello Dinh,
The function looks good. Are you using the same limits in Geogebra?
Dinh Le Dung
Dinh Le Dung 2022년 5월 3일
This is what Matlab gives
This is what Geogebra gives.
They look pretty much not the same :((
Walter Roberson
Walter Roberson 2022년 5월 3일
Very different plotting ranges.
Dinh Le Dung
Dinh Le Dung 2022년 5월 3일
I see, thanks for your help sir!

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 채택된 답변

Stephen23
Stephen23 2022년 5월 3일
편집: Stephen23 2022년 5월 3일

1 개 추천

"I think there is a problem with .*exp(x-y)"
I doubt that. Did you look at the domains and ranges that you are plotting?
Your Geogebra example shows that you plotted over x = -8..+8 and y = -8..+8. Then in MATLAB you plotted over x = -1..1 and y = -2..2. And then you did not limit the Z axes to the same range as your example plot. Lets try that now:
x = -8:0.5:8;
y = -8:0.5:8;
[X,Y] = meshgrid(x,y);
T = (X.^2-2*Y.^2).*exp(X-Y);
surf(X,Y,T);
zlim([-3,6])

추가 답변 (1개)

Catalytic
Catalytic 2022년 5월 2일

1 개 추천

If I had to guess, you have x and y reversed.
[X, Y] = ndgrid(x, y);
surf(X, Y, t(X,Y));

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