Index in Positon 1 is invalid

Hello everyone, sadly I have an error that I personally don't really understand, maybe one of you will able to help me, so thanks a lot in advance for that.

So for a task for the university I'm trying to shorten the script a lot by creating a vector through a loop, but I constantly get the error that my Index is invalid.

My aim is to get a 0:14 long vector that contains the following equation for each row depending on n, but sadly it isn't working as planed, i would be really grateful if someone could help me to find my problem here.

for n=0:14

x1=5*sin(2*pi*F1*(kT-n*T));

x2=0.3*cos(2*pi*F2*(kT-n*T));

x=x1+x2;

xv(n,:)=x

end

Error: Index in position 1 is invalid. Array indices must be positive integers or logical values.

Sincerely Jan C. Faber

Answer 1

[Voss]

Indexing in MATLAB starts at 1, so when n == 0, referring to xv(n,:) gives you that error.

One way to fix it is to add 1 to n when you use it as an index, so that n = 0 through n = 14 correspond to rows 1 through 15 of xv:

for n=0:14
    x1=5*sin(2*pi*F1*(kT-n*T));
    x2=0.3*cos(2*pi*F2*(kT-n*T));
    x=x1+x2;
    
%     xv(n,:)=x
    xv(n+1,:)=x
    
    
    
end

Answer 2

[Steven Lord]

MATLAB indexing is 1-based not 0-based.

The first element / row / column / etc. of an array in MATLAB is element / row / column / etc. 1 not 0.

Answer 3

[Jan Faber]

If I could, then I would love to accept both answers, thanks a lot both of you.