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how to find mean from cell

조회 수: 1 (최근 30일)
Thar
Thar 2015년 1월 20일
편집: Star Strider 2015년 1월 20일
Hi all!
I have the matrix:
M=[Finally(:,1:8)];
S=[Finally(:,9:2012)];
and
Mc= mat2cell(M, rows, 8);
Sc= mat2cell(S, rows, 2004);
I want to find the means of Mc and Sc.
I have the script
for k1 = 1:size(Mc,1)
W(k1)=mean(Mc{k1}(1:end,1));
end
but it doesn't work.
Is anything wrong?
Thank you!
  댓글 수: 2
Guillaume
Guillaume 2015년 1월 20일
You'll have to clarify, the 'it doesn't work' by posting the entire error message that you get (including the line that errors out).
As it is, your code should work. Here is a slight rewrite:
M = rand(100, 8); %demo data
rows = 20 * ones(1, size(M, 1)/20); %demo data
Mc = mat2cell(M, rows, size(M, 2));
W = cellfun(@(m) mean(m(:, 1)), Mc);
Star Strider
Star Strider 2015년 1월 20일
편집: Star Strider 2015년 1월 20일
This looks familiar.
Thodoris, how do you calculate your ‘rows’ variable? That is likely what we will need to Answer your Question.

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답변 (1개)

Titus Edelhofer
Titus Edelhofer 2015년 1월 20일
Hi,
first of all, why do you convert the matrix to a cell? Why not call mean for M? It should give you the mean for all columns directly. Second, using Mc{k1}(1:end,1) can be simplified by Mc{k1}(:,1). Third, "It doesn't work" sounds like you get an error message. Tell us the error message and it will be easier for us to diagnose.
Titus
  댓글 수: 1
Thar
Thar 2015년 1월 20일
I want to convert the matrix to a cell, because i have the step for the mean values to the rows. The message is that the dimensions are wrong.

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