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Why the responses of the following equations are nothing?

조회 수: 1 (최근 30일)
Marzieh Nodeh
Marzieh Nodeh 2022년 4월 21일
댓글: Star Strider 2022년 4월 25일
I'm trying to find aeq from the following equations. There are 3 equations with 3 unknowns. but the final response is empty brackets for all unknowns. Could you help me to solve this equation.
Regards,
syms ae gama A
eq1= (23.4255*(ae^3))+(1.2308e-06*ae)+gama
eq2= (A/(6*23.4255))-((2*1.2308e-06)/A)-ae
eq3= A-((((-108*gama)+(12*(sqrt(3*(((4*(1.2308e-06^2))+(27*(gama^2)*23.4255))/23.4255)))))*(23.4255^2)))^(1/3)
eqs= [eq1, eq2, eq3]
[ae,gama,A]=vpasolve(eqs, [ae,gama,A])
%reported results
ae =
[ empty sym ]
gama =
[]
A =
[]

답변 (1개)

Star Strider
Star Strider 2022년 4월 21일
Use solve then vpa
syms ae gama A
eq1= (23.4255*(ae^3))+(1.2308e-06*ae)+gama
eq1 = 
eq2= (A/(6*23.4255))-((2*1.2308e-06)/A)-ae
eq2 = 
eq3= A-((((-108*gama)+(12*(sqrt(3*(((4*(1.2308e-06^2))+(27*(gama^2)*23.4255))/23.4255)))))*(23.4255^2)))^(1/3)
eq3 = 
eqs= [eq1, eq2, eq3]
eqs = 
[ae,gama,A]=solve(eqs, [ae,gama,A]);
Warning: Possibly spurious solutions.
ae = vpa(ae,7)
ae = 
gama = vpa(gama,7)
gama = 
A = vpa(A,7)
A = 
Also consider double instead of vpa, depending on the result you want.
.
  댓글 수: 6
Marzieh Nodeh
Marzieh Nodeh 2022년 4월 25일
Perfect. Thank you very much for your help.
Star Strider
Star Strider 2022년 4월 25일
My pleasure!
If my Answer helped you solve your problem, please Accept it!
.

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